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DOS学习入门 & 精彩文章（教学室） » How can I assign the output of a command to a variable? Thanks

Floor1　msg	Posted 2003-08-24 00:00
初级用户　Posts 2　Credits 108
I wrote a batch file. The original idea was to display today's date in YYYYMMDD format, but instead it shows type date.txt, My bat file is as follows: @call date /t \| awk95 -F- "{ print($1 $2 substr($3,1,2)) }">date.txt @set filename=type date.txt echo %filename% Thanks, many thanks

Floor2　iceboy	Posted 2003-08-30 00:00
银牌会员　Posts 512　Credits 1,681
If you want to display it on the screen, then use type date.txt... If you want to assign it to a variable... you may need to write a small program in QB

Floor3　willsort	Posted 2003-08-30 00:00
元老会员　Posts 1,512　Credits 4,432
Re msg： First write a file, you can name it setfile.tmp, with the content “set filename=”. Note that the file must not contain a carriage return character, so you can't use edit to edit it, or if you use edit, then use debug to delete the last two bytes afterward. Next, change the line @set filename=type date.txt in the program to @copy setfile.tmp+date.txt setfile.bat >nul @call setfile.bat

Floor4　iceboy	Posted 2003-09-05 00:00
银牌会员　Posts 512　Credits 1,681
Hehe, it's best to use copy /b, otherwise problems are very likely to occur (especially when using EDIT to write setfile.tmp)

Floor5　willsort	Posted 2003-10-31 00:00
元老会员　Posts 1,512　Credits 4,432
Re iceboy: I don't see what effect /b has on this problem. I only know that it is just meant to avoid mistakenly interpreting and executing certain characters in a binary file according to their uses in the ASCII table. And in my solution, if the temporary file carries a carriage return character, then whether /b is used or not, the correct result will not be obtained. Also, isn't copy's default parameter /b rather than /a?