The return code of the choice command is arranged in the order of the specified options. For example, in choice /c:dme defrag,mem,end, the return code for 'd' (defrag) is 1, the return code for'm' (mem) is 2, and the return code for 'e' (end) is 3. If you swap the order, the return code will change. For example, in choice /c:dem defragend,mem, the return code for 'd' (defragend) is 1, the return code for 'e' (end) is 2, and the return code for'm' (mem) is 3.
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中国DOS联盟论坛 » DOS学习入门 & 精彩文章 （教学室） » About the choice command
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Posted 2003-08-16 00:00 · 中国 浙江 杭州 余杭区 电信
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Posted 2003-08-16 00:00 · 中国 浙江 杭州 电信
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Why is there no one to help me?
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Posted 2003-08-16 00:00 · 中国 香港 有线电视
The following is a quote from hotdog on 2003-8-16 3:12:22:
What is the order of the return codes for the choice command, like 1234...
For example, choice /c:dme defrag,mem,end
Which return code is 1
Which is 2
Which is 3
Does swapping the order change the return codes?
For example, choice /c:dem defrag,end,mem
Which brother can help answer?
choice /c:dem defrag,end,mem
^----Return code is 1
^---Return code is 2
^--Return code is 3
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Posted 2003-08-16 00:00 · 中国 浙江 杭州 余杭区 电信
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Then why is it written like this? Can you explain it?
@echo off
choice /c:dme defrag,mem,end
if errorlevel 3 goto defrag
if errorlevel 2 goto mem
if errotlevel 1 goto end
@echo off
choice /c:dme defrag,mem,end
if errorlevel 3 goto defrag
if errorlevel 2 goto mem
if errotlevel 1 goto end
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Posted 2003-08-16 00:00 · 中国 广东 肇庆 电信
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It's just that writing it like this is clearer!
You can write it like this:
choice /c:dme d,m,e
It can also be written like this:
choice /c:dme
The result is the same!
You can write it like this:
choice /c:dme d,m,e
It can also be written like this:
choice /c:dme
The result is the same!
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Posted 2003-08-16 00:00 · 中国 广东 肇庆 电信
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It's just that the prompts on the screen are different!
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Posted 2003-08-16 00:00 · 中国 香港 有线电视
The following is a quote from hotdog on 2003-8-16 16:46:38:
Then may I ask why it is written like this
Can you explain it
@echo off
choice /c:dme defrag,mem,end
if errorlevel 3 goto defrag
if errorlevel 2 goto mem
if errotlevel 1 goto end
You made a mistake.....
It should be like this:
@echo off
choice /c:dme defrag,mem,end
if errorlevel 3 goto end
if errorlevel 2 goto mem
if errotlevel 1 goto defrag
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Posted 2003-08-16 00:00 · 中国 广东 肇庆 电信
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The following is the speech of Roy on 2003-8-16 17:02:12:Hehe! I didn't pay attention either;
The following is the speech of hotdog on 2003-8-16 16:46:38:
Then, may I ask why it is written like this
Can you explain it
@echo off
choice /c:dme defrag,mem,end
if errorlevel 3 goto defrag
if errorlevel 2 goto mem
if errotlevel 1 goto end
You made a mistake.....
It should be like this:
@echo off
choice /c:dme defrag,mem,end
if errorlevel 3 goto end
if errorlevel 2 goto mem
if errotlevel 1 goto defrag
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Posted 2003-08-16 00:00 · 中国 重庆 电信
Please clarify your specific context. The "if errorlevel 3 goto end" in batch scripting means if the error level of the previous command is greater than or equal to 3, then jump to the label "end". But without the full context of the surrounding batch code, it's hard to be more precise about which specific command's error it refers to. But based on the general syntax, that's the basic meaning. Please provide more context if possible.
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Posted 2003-08-16 00:00 · 中国 湖南 湘潭 电信
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If the choice is 3, then execute end
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Posted 2003-08-16 00:00 · 中国 浙江 杭州 余杭区 电信
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I see. Thanks.
Floor 12
Posted 2003-08-16 00:00 · 中国 重庆 电信
The following is a quote from zl7322 on 2003-8-16 22:42:11:
If you choose 3, it will execute end
Where is this 3 chosen? Isn't batch processing executed sequentially?
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Posted 2003-08-17 00:00 · 中国 浙江 杭州 电信
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Posted 2004-06-24 00:00 · 中国 广东 广州 联通
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Been looking for this!
www.51ct.net
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Posted 2004-06-24 00:00 · 中国 黑龙江 大庆 大庆中基石油通信建设有限公司
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What does the choice command mean
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