China DOS Union

I want to write a batch file with the following requirements:
1. The value in file test.txt is 0 or 1;
2. If the read value is 0, call a.exe, if the read value is 1, call b.exe

This is the batch file I wrote:
FOR /F "delims=" %%a in (test.txt) do if "%%a"=="0" (call a.exe) else call b.exe
When executed under DOS 6.22, it reports a syntax error. Please help rewrite it, thank you!

[ Last edited by kaixin1228 on 2009-9-15 at 22:50 ]

The return code read by batch processing can only be %ERRORLEVEL%

1. echo;%%a to see what is returned exactly
2. Upload your test.exe
3. If you don't need to write if so complicated, if %%a only has the possibility of 0 or 1, then it can be directly written as if %%a equ 0 (call a.exe) else call b.exe or if %%a equ 1 (call b.exe) else call a.exe

The source code of test.exe is as follows:

unsigned char main(void)
{
unsigned char value=0;

value=inport(0x1e8);
return value;
}

Just tried the return value:
for /f %%a in(test.exe) do echo %%a

Reports a syntax error

[ Last edited by kaixin1228 on 2009-9-15 at 05:56 ]

You can try it like this:
test.exe>nul 2>nul if %ERRORLEVEL% equ 0 (echo Return 0 or default to 0) else echo Success returns 1 pause
After the test is successful, change it to:
test.exe>nul 2>nul if %ERRORLEVEL% equ 0 (call a.exe) else call b.exe

[ Last edited by Hanyeguxing on 2009-9-15 at 06:07 ]

It reports Syntax error

CMD should not return the %errorleve% of an external program, unless that program returns an errorlevel to CMD. For example, the command line of 7Z, when decompressed correctly, returns 0 to CMD. Hehe, just talking nonsense, I don't know very well.