China DOS Union

I'm a newbie and don't know DOS very well.
I want to make a boot disk to serve as the boot files for a CD,
so that after the machine starts up it can automatically switch to the CD-ROM drive letter.
How should the batch file be written?
What other files are needed on the disk?

Please take the time to answer this, thank you!!

No files are needed at all... as long as the batch file loads the CD-ROM drive at startup, that's enough.
I've talked about it in this section before, please look for it. Thanks... If you really can't find it, I'll explain it again...

Thank you, master!
I really can't find it.
Please explain it after all.
Please be detailed, I only know how to use common commands like format, fdisk, cd, etc.
Thanks!

I think this has already been covered in the boot disk section, right...

In the autoexec.bat on the win98 boot disk, change the line set cdrom= to %cdrom%:

The following is quoted from 电吉入侵 at 2003-7-6 19:41:59:
In the autoexec.bat on the win98 boot disk, change the line set cdrom=  to %cdrom%:

That won't work. That boot disk doesn't have the %CDROM% variable.

My Super MS-DOS 7.10 boot disk does have the %CDROM% variable... for details, please see the "DOS Boot Disk" section.

This is a repeated question, and I've already replied over there. The content is as follows:

If you already know how to use a boot floppy to make a bootable CD, and only don't know how to automatically switch to the CD-ROM drive letter after booting,
then you only need to solve the problem of finding the CD-ROM drive letter.
There are two methods:
1.Specify the CD-ROM drive letter: add /L:X to the end of the line with MSCDEX.EXE in AUTOEXEC.BAT on the boot floppy (X can be replaced with another letter). Note that CONFIG.SYS should contain this line: LASTDRIVE=Z
This method is simple and easy to use, recommended for beginners.
2.Use FINDCD.EXE to find the CD-ROM drive letter. This method is a bit more complicated; you can refer to the super moderator's MSDOS7.10 Super Boot Disk.

After deciding which method to use, add one more line at the end of AUTOEXEC.BAT on the boot floppy:
X: (the first method)
or
%CDROM%: (the second method)

Then after booting, you can enter the CD-ROM drive letter (of course, the drive letter of the first CD-ROM drive).

You can test it with a floppy disk first, and burn the CD after it works.

If you still don't know how to use a boot floppy to make a bootable CD, then first look through the old posts from before; after you learn that, do the above.

The following is quoted from Wengier at 2003-7-6 19:58:22:

The following is quoted from 电吉入侵 at 2003-7-6 19:41:59:
In the autoexec.bat on the win98 boot disk, change the line set cdrom=  to %cdrom%:

That won't work. That boot disk doesn't have the %CDROM% variable.

My Super MS-DOS 7.10 boot disk does have the %CDROM% variable... for details, please see the "DOS Boot Disk" section.

How could it not have it? Wengier, look more carefully. I can use %cdrom%: to enter the CDROM just by deleting the set cdrom= line at the end.

It really works now!
电吉入侵, thank you!!!
Thanks, everyone!

Impressive!!! Impressive!!!

The %CDROM% variable in that boot disk is completely preset, and not obtained directly at all...

:do_shift
set cdrom=%2
shift

That's right, isn't it! And this will reduce compatibility.

Shouldn't it come from LH %ramd%:\MSCDEX.EXE /D:mscd001 /L:%CDROM% here?
Wengier, take a look and see if that's the case. Will this cause compatibility problems?
But why did Microsoft remove this variable at the end...

But that findcd of yours is still pretty useful (I'm using it^^)