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DOS学习入门 & 精彩文章 (教学室) » Question for the experts: about low-level formatting a hard disk with DEBUG!!
Printable Version  1,177 / 5
Floor1 onlylink Posted 2003-06-29 00:00
初级用户 Posts 2 Credits 109
Everyone, please take a look and see if this is right
debug
-a
------ mov ax,33f
------ mov cx,200
------ mov cx,1
------mov dx,80
------ int 13
----- int 3
------ enter

-g 9999 0 2
-g
-q
Please give me lots of advice!!
Floor2 defrag Posted 2005-01-01 00:00
中级用户 Posts 570 Credits 456
That's called a quick full-disk high-level format!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Floor3 MM521 Posted 2005-01-07 00:00
初级用户 Posts 2 Credits 115
Explain it, I can't understand it
Floor4 xlxlds Posted 2005-01-08 00:00
初级用户 Posts 14 Credits 141
Could an expert explain how to translate this stuff into plain Chinese? I've also learned some basics of assembly and DEBUG, and I know the surface meaning of it; I can understand single instructions too.] But when you put them together, what function do they form? It's really a complete mess. For the DEBUG above, I know every line, but I just don't know what it means as a whole. I really want to know how to read programs—what else should I learn, and are there any better teaching materials!!!!========================================Don't blame me for being long-winded, I don't want to be like this either!! But who told other people to be so good at this??!!
Floor5 xlxlds Posted 2005-01-25 00:00
初级用户 Posts 14 Credits 141
Huh? Why's nobody here anymore?
Floor6 bush Posted 2005-01-25 00:00
银牌会员 Posts 730 Credits 2,165
I don't really understand it either; it requires knowledge about disk information, (mainly the problem of interrupt calls)
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