中国DOS联盟

@echo off
set a=one
set b=two
echo/Before call :swap a b
call :Swap a b
echo/After call 1 :swap a b
call :Swap b a
echo/After call 2 :swap b a
pause
goto :EOF

:Swap
call set a=%%%1%%
call set b=%%%2%%
set "%1=%b%" & set "%2=%a%" & goto :EOF

----------------------------------------------------------------------
显示结果:
Before call :swap a b
After call 1 :swap a b
After call 2 :swap b a

实在不解，求解答..

echo/After call 2 :swap b a 时
call set a=%%%1%%
call set b=%%%2%%
因为%1=b，%2=a
也就是
set a=!b!
set b=!a!
所以对于值来说!a!=!b!=one

[ Last edited by Hanyeguxing on 2010-4-12 at 14:04 ]

又是你的回答，先感谢！！

哦，原来是这样的!!

我都把CALL带下来的变量当值来call set 了，难怪two不见了。.额