『第 57 楼』:
 
 
使用 LLM 解释/回答一下
  
请看罗云彬的源码例: 
.286 
CODE		SEGMENT 
		ASSUME CS:CODE,DS:CODE 
		ORG 100H 
START: 
		jmp	install 
;   ........       0000 0000      00h 
;   ..xxxxxx      0011 1111      3fh 
;   .x......       0100 0000      40h 
;   .x.xxxxx      0101 1111       5fh 
;   .x.x..x.      0101 0010       52h 
;   .xxx.x..      0111 0100       74h 
;   ....x.xx      0000 1011       0bh 
;   ...x.x..      0001 0100       14h 
;   ..x.x..x      0010 1001      29h 
;   .x..x.x.      0100 1010       4ah 
;   .x..x..x      0100 1001      49h 
;   .x...x..      0100 0100       44h 
;   .x....xx      0100 0011       43h 
;   ..xxxxxx       0011 1111      3fh 
;   ........      0000 0000       00h 
;   ........      0000 0000       00h 
 
CHAR    db     00h,3fh,40h,5fh,52h,74h,0bh,14h         ;left part of phone 
        db     29h,4ah,49h,44h,43h,3fh,00h,00h 
 
        db     00h,0f8h,04h,0f4h,094h,5ch,0a0h,50h    ;right part of phone 
        db     28h,0a4h,24h,44h,84h,0f8h,00h,00h 
 
STRn    db    'This is a phone:',0ceh,0cfh,'$' 
 
install: 
        mov    ax,1100h             ;功能号 
        mov    bx,1000h             ;BH=10H,每字符点阵为16字节 
        mov    cx,2                 ;共要装入2字节 
        mov    dx,00ceh             ;从00CEH开始(00CEH,00CFH) 
        push ds 
        pop es 
        mov    bp,offset char       ;ES:BP为字符点阵数据地址 
        int    10h 
 
        mov    ah,9                 ;把字符 ce,cf显示出来看看,是什么! 
        mov    dx,offset strn 
        int    21h 
        ret 
CODE		ENDS 
		END START 
Please provide the specific part that needs to be translated. If you want the entire content translated, here it is: 
 
Please look at the source code example of Luo Yunbin: 
 
.286 
CODE		SEGMENT 
		ASSUME CS:CODE,DS:CODE 
		ORG 100H 
START: 
		jmp	install 
;   ........       0000 0000      00h 
;   ..xxxxxx      0011 1111      3fh 
;   .x......       0100 0000      40h 
;   .x.xxxxx      0101 1111       5fh 
;   .x.x..x.      0101 0010       52h 
;   .xxx.x..      0111 0100       74h 
;   ....x.xx      0000 1011       0bh 
;   ...x.x..      0001 0100       14h 
;   ..x.x..x      0010 1001      29h 
;   .x..x.x.      0100 1010       4ah 
;   .x..x..x      0100 1001      49h 
;   .x...x..      0100 0100       44h 
;   .x....xx      0100 0011       43h 
;   ..xxxxxx       0011 1111      3fh 
;   ........      0000 0000       00h 
;   ........      0000 0000       00h 
 
CHAR    db     00h,3fh,40h,5fh,52h,74h,0bh,14h         ;left part of phone 
        db     29h,4ah,49h,44h,43h,3fh,00h,00h 
 
        db     00h,0f8h,04h,0f4h,094h,5ch,0a0h,50h    ;right part of phone 
        db     28h,0a4h,24h,44h,84h,0f8h,00h,00h 
 
STRn    db    'This is a phone:',0ceh,0cfh,'$' 
 
install: 
        mov    ax,1100h             ;Function number 
        mov    bx,1000h             ;BH=10H, each character dot matrix is 16 bytes 
        mov    cx,2                 ;Total 2 bytes to load 
        mov    dx,00ceh             ;Start from 00CEH (00CEH, 00CFH) 
        push ds 
        pop es 
        mov    bp,offset char       ;ES:BP is the character dot matrix data address 
        int    10h 
 
        mov    ah,9                 ;Display characters ce, cf to see what it is! 
        mov    dx,offset strn 
        int    21h 
        ret 
CODE		ENDS 
		END START 
    
 
  
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