中国DOS联盟

ROBOCOPY log

-------------------------------------------------------------------------------
ROBOCOPY :: Robust File Copy for Windows :: Version XP010
-------------------------------------------------------------------------------

Started : Sat Oct 02 22:47:20 2010

Source = R:\lftp\
Dest = R:\-10-02\

Files : *.*

Options : *.* /FP /NS /NDL /L /S /E /COPY:DAT /PURGE /MIR /NP /R:1000000 /W:30

------------------------------------------------------------------------------

Newer R:\lftp\lftp-install.txt
New File R:\lftp\lftp-install.txt.bak

------------------------------------------------------------------------------

Total Copied Skipped Mismatch FAILED Extras
Dirs : 2 0 2 0 0 0
Files : 11 2 9 0 0 0
Bytes : 1.81 m 5.4 k 1.81 m 0 0 0
Times : 0:00:00 0:00:00 0:00:00 0:00:00

Ended : Sat Oct 02 22:47:20 2010

@echo off
for /f "tokens=2* delims=R" %%i in ('findstr /i "New"

robocopy.log') do echo R%%i%%j
pause

显示的结果是 两条记录
Newer R:\lftp\lftp-install.txt
New File R:\lftp\lftp-install.txt.bak


怎么才能方便的显示出来总共有两条新记录？

@echo off
for /f "tokens=2* delims=R" %%i in ('findstr /i "New"

robocopy.log') do （echo R%%i%%j

echo 总共%N%t条记录
)
pause

我网上看到一段代码计数的。但是试了几次无法和上面这段结合起来 老是出错
谁能帮帮我


@echo off
for /l %%a in (1,1,10) do (call :abc %%a)
goto :eof
:abc
set "v=%~1"
echo %v%
pause
goto :eof


谢谢

@echo off

for /f "tokens=2* delims=R" %%i in ('findstr /i "New"

robocopy.log') do （echo R%%i%%j

call :abc

)
goto :eof
echo 总共%N%条记录

pause

:abc
set "N=%~1"
echo %N%
pause
goto :eof

知道了。。。。。。。





set a=0
for /f "tokens=2* delims=R" %%i in ('findstr /i "New"

robocopy.log') do （

set /a a+=1

)

echo %a% files been updated