跪求把这段汇编转换成C语言！！谢谢啦！！！ - 中国DOS联盟论坛

一，happy birthday 生日快乐歌用21个音阶设计的程序
Void happy birthday()要用C51格式写程序！
{
setb tr0（tr0=1;）；启动定时器0
start0:
setb p3.3;
30h=0x00;
next:
mov a,30h
mov dptr,#table
inc dptr
movc a,@a+dptr
mov r5,a ；将节拍码存入r5
cjne a,#0ffh,next1
jmp ennd
next1:
clr c
mov a,dpl
subb a,#1
mov dpl,a
mov a,dph
subb a,#0
mov dph,a
mov a,30h
movc a,@a+dptr
jnz sing
clr tr0 ；休止符？是，则不发音
jmp d1 ；跳到d1
sing:
dec a ；取到的音符码减1
mov 22h,a ；存入（22h)
rl a ；乘2
mov dptr,#table1 ；至table1取相对应的高字节
movc a,@a+dptr
mov th0,a ；取到的高字节存入TH0
mov 21h,a ；取到的高字节存入（21h)
mov a,22h ；乘2
rl a ；加1
inc a ；至table1取相对应的低位
movc a,@a+dptr
mov tl0,a ；取到低字节存入tl0
mov 20h,a ；取到低字节存入（20h)
setb tr0 ；启动timer0
d1:
call delay ；声音延时基本单位时间 1/4拍187毫秒
inc 30h ；取简码简指针加1
inc 30h ；取简码简指针加1
jmp next ；取下一个码
ennd:
clr tr0 ；停止timer0
ret
table:
db 12,2,0,1,12,2,13,4,12,4,15,4,14,4,0,4
db 12,2,0,1,12,1,13,4,12,4,16,4,15,4,0,4
db 12,2,0,1,12,1,19,4,17,4,15,4,14,4,13,4
db 18,2,0,1,18,1,17,4,15,4,16,4,15,4,0,4
db 12,2,0,1,12,1,13,4,12,4,15,4,14,4,0,4
db 12,2,0,1,12,1,13,4,12,4,16,4,15,4,0,4
db 12,2,0,1,12,1,19,4,17,4,15,4,14,4,13,4
db 18,2,0,1,15,1,17,4,15,4,16,4,15,4,0,4,0ffh,0ffh

}

我乱写了一个，应该是有错误的，没测试，只供参考
应该适合turboc




#include <dos.h>

#define DELAY 168
#define SIZE  130

typedef unsigned char BYTE;

int main(int argc, char *argv)
{
	BYTE  music = {
	 						 2,2,0,1,12,2,13,4,12,4,15,4,14,4,0,4,
							12,2,0,1,12,1,13,4,12,4,16,4,15,4,0,4,
							12,2,0,1,12,1,19,4,17,4,15,4,14,4,13,4,
							18,2,0,1,18,1,17,4,15,4,16,4,15,4,0,4,
							12,2,0,1,12,1,13,4,12,4,15,4,14,4,0,4,
							12,2,0,1,12,1,13,4,12,4,16,4,15,4,0,4,
							12,2,0,1,12,1,19,4,17,4,15,4,14,4,13,4,
							18,2,0,1,15,1,17,4,15,4,16,4,15,4,0,4,
							0ffh,0ffh
		
						}

	for ( i = 0 ; i < SIZE; i++ )
	{
		sound(music);
		delay(DELAY);

	}
	
	nosound();

	return 0;
}

应该要把数组里的值再做一下运算，不然这么低的频率应该听不到。。。

蜂鸣器发音吗??

LZ是MCS51单片机的程序，当然不能用基于X86的Turbo C，2楼的程序当然不行。不知LZ所用的编译器可是Keil C?由于C51系列兼容单片机程序存储器容量通常很小(AT89C51为4KB)，而C语言的编译效率并不高，在C51使用C语言开发通常意味着要增加不少硬件成本，个人强力推荐在低端单片机开发直接使用汇编。
另，单片机开发要附上电路图(起码要简图)，否则很难理解LZ的用意。

LZ的这段程序只需稍加改动,应该可以嵌入到Keil C51里的,就象TC一样,它也支持嵌入汇编;另外,你可以学习一下Keil C51,如:象启动定时器0只需写入TR0=1即可,等等....不一一例举.

c51没写过,不过x86还可以.作者的代码差table1和delay.
下面代码已经将table1补全.


short table1 = { // frequency table
//    1    2    3    4     5     6     7
//	                                  82,
//	 87,  98, 110, 124,  131,  147,  165,
	175, 196, 220, 247,  262,  294,  330,
	349, 392, 440, 494,  523,  587,  659,
	698, 784, 880, 988, 1047,
};

char table = { // music map, pairs of (tone, beat)
	12,2,0,1,12,2,13,4,12,4,15,4,14,4,0,4,
	12,2,0,1,12,1,13,4,12,4,16,4,15,4,0,4,
	12,2,0,1,12,1,19,4,17,4,15,4,14,4,13,4,
	18,2,0,1,18,1,17,4,15,4,16,4,15,4,0,4,
	12,2,0,1,12,1,13,4,12,4,15,4,14,4,0,4,
	12,2,0,1,12,1,13,4,12,4,16,4,15,4,0,4,
	12,2,0,1,12,1,19,4,17,4,15,4,14,4,13,4,
	18,2,0,1,15,1,17,4,15,4,16,4,15,4,0,4,-1,-1
};

void c51_delay(char beat)
{
	int delay;
	delay = beat * 187;
//  sleep of delay ms
}

void c51_start_timer0()
{
//	TR0 = 1;
}

void c51_stop_timer0()
{
//	TR0 = 0;
}

void c51_make_sound(char tone)
{
	union {
		short word;
		char byte;
	}u;

	u.word = table1;
//	TH0 = u.byte;
//	TL0 = u.byte;
}

void c51_happy_birthday(void)
{
	int i;

	c51_start_timer0();
	for (i = 0; table != -1; i += 2) {
		if (table == 0) {
			c51_stop_timer0();
		}else {
			c51_make_sound(table);
			c51_start_timer0();
		}
		c51_delay(table);
	}
	c51_stop_timer0();
}

#include <windows.h>

void happy_birthday(void)
{
	int i;
	int delay;

	for (i = 0; table != -1; i += 2) {
		delay = table * 187;
		if (table == 0) {
			Sleep(delay);
		}else {
			Beep(table1 - 1], delay);
		}
	}
}

int main(void)
{
	happy_birthday();
	return 0;
}

第1楼　zj57421017	发表于 2010-05-08 19:19
新手上路　发帖 2　积分 5
跪求把这段汇编转换成C语言！！谢谢啦！！！一，happy birthday 生日快乐歌用21个音阶设计的程序 Void happy birthday()要用C51格式写程序！ { setb tr0（tr0=1;）；启动定时器0 start0: setb p3.3; 30h=0x00; next: mov a,30h mov dptr,#table inc dptr movc a,@a+dptr mov r5,a ；将节拍码存入r5 cjne a,#0ffh,next1 jmp ennd next1: clr c mov a,dpl subb a,#1 mov dpl,a mov a,dph subb a,#0 mov dph,a mov a,30h movc a,@a+dptr jnz sing clr tr0 ；休止符？是，则不发音 jmp d1 ；跳到d1 sing: dec a ；取到的音符码减1 mov 22h,a ；存入（22h) rl a ；乘2 mov dptr,#table1 ；至table1取相对应的高字节 movc a,@a+dptr mov th0,a ；取到的高字节存入TH0 mov 21h,a ；取到的高字节存入（21h) mov a,22h ；乘2 rl a ；加1 inc a ；至table1取相对应的低位 movc a,@a+dptr mov tl0,a ；取到低字节存入tl0 mov 20h,a ；取到低字节存入（20h) setb tr0 ；启动timer0 d1: call delay ；声音延时基本单位时间 1/4拍187毫秒 inc 30h ；取简码简指针加1 inc 30h ；取简码简指针加1 jmp next ；取下一个码 ennd: clr tr0 ；停止timer0 ret table: db 12,2,0,1,12,2,13,4,12,4,15,4,14,4,0,4 db 12,2,0,1,12,1,13,4,12,4,16,4,15,4,0,4 db 12,2,0,1,12,1,19,4,17,4,15,4,14,4,13,4 db 18,2,0,1,18,1,17,4,15,4,16,4,15,4,0,4 db 12,2,0,1,12,1,13,4,12,4,15,4,14,4,0,4 db 12,2,0,1,12,1,13,4,12,4,16,4,15,4,0,4 db 12,2,0,1,12,1,19,4,17,4,15,4,14,4,13,4 db 18,2,0,1,15,1,17,4,15,4,16,4,15,4,0,4,0ffh,0ffh }

第2楼　070	发表于 2010-05-10 17:14
高级用户　发帖 218　积分 663　来自福建
我乱写了一个，应该是有错误的，没测试，只供参考应该适合turboc #include <dos.h> #define DELAY 168 #define SIZE 130 typedef unsigned char BYTE; int main(int argc, char *argv) { BYTE music = { 2,2,0,1,12,2,13,4,12,4,15,4,14,4,0,4, 12,2,0,1,12,1,13,4,12,4,16,4,15,4,0,4, 12,2,0,1,12,1,19,4,17,4,15,4,14,4,13,4, 18,2,0,1,18,1,17,4,15,4,16,4,15,4,0,4, 12,2,0,1,12,1,13,4,12,4,15,4,14,4,0,4, 12,2,0,1,12,1,13,4,12,4,16,4,15,4,0,4, 12,2,0,1,12,1,19,4,17,4,15,4,14,4,13,4, 18,2,0,1,15,1,17,4,15,4,16,4,15,4,0,4, 0ffh,0ffh } for ( i = 0 ; i < SIZE; i++ ) { sound(music); delay(DELAY); } nosound(); return 0; } 应该要把数组里的值再做一下运算，不然这么低的频率应该听不到。。。

第3楼　523066680	发表于 2010-05-11 22:31
银牌会员　发帖 1,133　积分 2,361
蜂鸣器发音吗??

第4楼　netwinxp	发表于 2010-05-30 16:56
高级用户　发帖 366　积分 741
LZ是MCS51单片机的程序，当然不能用基于X86的Turbo C，2楼的程序当然不行。不知LZ所用的编译器可是Keil C?由于C51系列兼容单片机程序存储器容量通常很小(AT89C51为4KB)，而C语言的编译效率并不高，在C51使用C语言开发通常意味着要增加不少硬件成本，个人强力推荐在低端单片机开发直接使用汇编。另，单片机开发要附上电路图(起码要简图)，否则很难理解LZ的用意。

第5楼　cnch	发表于 2010-09-05 15:06
中级用户　发帖 70　积分 326
LZ的这段程序只需稍加改动,应该可以嵌入到Keil C51里的,就象TC一样,它也支持嵌入汇编;另外,你可以学习一下Keil C51,如:象启动定时器0只需写入TR0=1即可,等等....不一一例举.

第6楼　cobras	发表于 2010-09-10 17:43
新手上路　发帖 5　积分 14
c51没写过,不过x86还可以.作者的代码差table1和delay. 下面代码已经将table1补全. short table1 = { // frequency table // 1 2 3 4 5 6 7 // 82, // 87, 98, 110, 124, 131, 147, 165, 175, 196, 220, 247, 262, 294, 330, 349, 392, 440, 494, 523, 587, 659, 698, 784, 880, 988, 1047, }; char table = { // music map, pairs of (tone, beat) 12,2,0,1,12,2,13,4,12,4,15,4,14,4,0,4, 12,2,0,1,12,1,13,4,12,4,16,4,15,4,0,4, 12,2,0,1,12,1,19,4,17,4,15,4,14,4,13,4, 18,2,0,1,18,1,17,4,15,4,16,4,15,4,0,4, 12,2,0,1,12,1,13,4,12,4,15,4,14,4,0,4, 12,2,0,1,12,1,13,4,12,4,16,4,15,4,0,4, 12,2,0,1,12,1,19,4,17,4,15,4,14,4,13,4, 18,2,0,1,15,1,17,4,15,4,16,4,15,4,0,4,-1,-1 }; void c51_delay(char beat) { int delay; delay = beat * 187; // sleep of delay ms } void c51_start_timer0() { // TR0 = 1; } void c51_stop_timer0() { // TR0 = 0; } void c51_make_sound(char tone) { union { short word; char byte; }u; u.word = table1; // TH0 = u.byte; // TL0 = u.byte; } void c51_happy_birthday(void) { int i; c51_start_timer0(); for (i = 0; table != -1; i += 2) { if (table == 0) { c51_stop_timer0(); }else { c51_make_sound(table); c51_start_timer0(); } c51_delay(table); } c51_stop_timer0(); } #include <windows.h> void happy_birthday(void) { int i; int delay; for (i = 0; table != -1; i += 2) { delay = table * 187; if (table == 0) { Sleep(delay); }else { Beep(table1 - 1], delay); } } } int main(void) { happy_birthday(); return 0; }