中国DOS联盟

请问如何从路径中提取文件名? 例如 F:\md\abc\sdf.exe 文件名为 sdf.exe 请问如何提取？ 谢谢！

for /f %%i in ("F:\md\abc\sdf.exe") do echo %%~nxi

for /?

In addition, substitution of FOR variable references has been enhanced. You can now use the following optional syntax: %~I - expands %I removing any surrounding quotes (") %~fI - expands %I to a fully qualified path name %~dI - expands %I to a drive letter only %~pI - expands %I to a path only %~nI - expands %I to a file name only %~xI - expands %I to a file extension only %~sI - expanded path contains short names only %~aI - expands %I to file attributes of file %~tI - expands %I to date/time of file %~zI - expands %I to size of file %~$PATH:I - searches the directories listed in the PATH environment variable and expands %I to the fully qualified name of the first one found. If the environment variable name is not defined or the file is not found by the search, then this modifier expands to the empty string

Originally posted by balinger at 2008-7-4 12:23: for /f %%i in ("F:\md\abc\sdf.exe") do echo %%~nxi

如果路径中有空格就会出错，请问怎么解决？

for /f "tokens=*" %%i in (F:\md\abc\sdf.exe") do echo %%~nxi 这样就不怕空格了

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都已经解决了。来晚一步