中国DOS联盟

求助：自定义排序问题
如已有排号000001-000111，输入000111，自动从000112排序
我这样写的，不行啊
set/p a=输入6位已有排号的尾号后回车 :
Setlocal EnableDelayedExpansion
for /f "tokens=1* delims=:" %%i in ('findstr/n .* 0.txt') do (
set num=%a%%%i
set num=!num:~-6!
echo.[!num!]%%j >>1.txt
)

看了3楼的,发现自己理解错误,删除!

Last edited by moniuming on 2008-5-26 at 11:20 AM ]

@echo off&Setlocal EnableDelayedExpansion

set/p a=输入3位已有排号的尾号后回车 :

for /f "delims=" %%i in (0.txt) do (

     set /a a+=1

     echo  %%i>>1.txt

)

echo 搞定!

pause>nul

Last edited by zw19750516 on 2008-5-26 at 11:07 AM ]

谢谢您的回复，如从010000排就会超出6位了

谢谢6楼提醒,改过来了

@echo off

set/p a=输入6位已有排号的尾号后回车 :

set a=1%a%

set /a a+=1

echo %a:~-6%>>1.txt

echo 搞定!

pause>nul

Last edited by moniuming on 2008-5-26 at 12:53 PM ]

Originally posted by moniuming at 2008-5-26 11:55:

@echo off&Setlocal EnableDelayedExpansion

set/p a=输入6位已有排号的尾号后回车 :

for /f "delims=" %%i in (0.txt) do (

     set a=1%%a

     set /a a+=1

     echo ... 


set a=1%%a应该是set a=1%a%吧。
ps:set a=1%a%有创意，加分!

Last edited by zw19750516 on 2008-5-26 at 12:11 PM ]

Originally posted by moniuming at 2008-5-26 11:55:

@echo off&Setlocal EnableDelayedExpansion

set/p a=输入6位已有排号的尾号后回车 :

for /f "delims=" %%i in (0.txt) do (

     set a=1%a%

     set /a a+=1

     echo ... 




谢谢您的回复， 排号只加了一次并全部用了它，如输入000111，则全部用了000112哟

谢谢您的回复， 排号只加了一次并全部用了它，如输入000111，则全部用了000112哟

请问LZ要一直往下排多少呢

Originally posted by moniuming at 2008-5-26 13:04:

请问LZ要一直往下排多少呢

无法固定多少，有多少行就往下排多少， 如上例应该是000112，000113
000114.........， 您的却全是000112呀

试试这个?

@echo off

Setlocal EnableDelayedExpansion

for /f "delims=" %%i in (0.txt) do set a=1%%i

for /f "delims=" %%i in (0.txt) do (

   set /a a+=1

   >>1.txt echo !a:~-6!

)

pause

Last edited by moniuming on 2008-5-26 at 01:58 PM ]

Originally posted by moniuming at 2008-5-26 13:49:
试试这个?

@echo off

Setlocal EnableDelayedExpansion

for /f "delims=" %%i in (0.txt) do set a=1%%i

for /f "delims=" %%i in (0.txt) do (

   set /a a+=1

   >> ... 



还是不行呀

我已经试过成功了呀,把你的0.txt的内容贴出来看看,如果不是一行一串数字的话是不行的

c:\BJPrinter\CNMwindows\Canon S200SP\private.ini
c:\Documents and Settings\Administrator\Application Data\combobox_u.ini
c:\Documents and Settings\Administrator\Application Data\editplus_u.ini
c:\Documents and Settings\Administrator\Application Data\setting_u.ini
c:\Documents and Settings\Administrator\Application Data\SogouPY\correction.ini
c:\Documents and Settings\Administrator\Application Data\SogouPY\env.ini
c:\Documents and Settings\Administrator\Application Data\SogouPY\MoHuYin.ini
c:\Documents and Settings\Administrator\Application Data\SogouPY\scdlist.ini
c:\Documents and Settings\Administrator\Application Data\SogouPY\Skin\skin.ini
c:\Documents and Settings\Administrator\Local Settings\Temp\Set.ini
c:\Documents and Settings\Administrator\Local Settings\Temp\SogouPinYinUpdate.ini
c:\Documents and Settings\All Users\Application Data\Microsoft\Network\Connections\Pbk\sharedaccess.ini
c:\jjbxb\default.ini
c:\jjbxb\spyb.ini
c:\jjbxb\py\config.ini
c:\jjbxb\save\jjt.ini
c:\Program Files\epson\escndv\setup\ES_uninst.ini
c:\Program Files\epson\escndv\setup\setup.ini
...............

唉！
又见外星人 ！！！

知道LZ的意思了,这个应该没问题了吧

@echo off

Setlocal EnableDelayedExpansion

type nul>1.txt

for /f "tokens=1 delims=:" %%i in ('findstr /n .* 0.txt') do set a=100000%%i

for /f "delims=" %%i in (0.txt) do (

   set /a a+=1

   >>1.txt echo !a:~-6!  %%i

)

如果1.txt中原来就有000001-000111等内容,用下面的代码

@echo off

Setlocal EnableDelayedExpansion

set /p a=输入6位已有排号的尾号后回车 :

set b=1%a%

for /f "delims=" %%i in (0.txt) do (

   set /a b+=1

   >>1.txt echo !b:~-6!  %%i

)

Last edited by moniuming on 2008-5-26 at 03:35 PM ]