中国DOS联盟

1.txt
Pid Process Port Proto Path
140 -> 135 TCP
4 System -> 139 TCP
4 System -> 445 TCP
2316 -> 1032 TCP
1328 ccApp -> 1045 TCP C:\Program Files\Common Files\Symantec
1576 Sticky32 -> 3023 TCP C:\Program Files\Magic Notes\Sticky32.exe
0 System -> 4285 TCP
0 System -> 4287 TCP
0 System -> 4289 TCP
0 System -> 4291 TCP
0 System -> 4293 TCP
0 System -> 4295 TCP
0 System -> 4298 TCP

0 System -> 123 UDP
1328 ccApp -> 123 UDP C:\Program Files\Common Files\Symantec
0 System -> 137 UDP
0 System -> 138 UDP
140 -> 445 UDP
4 System -> 500 UDP
1576 Sticky32 -> 1025 UDP C:\Program Files\Magic Notes\Sticky32.exe
4 System -> 1026 UDP
0 System -> 1040 UDP
0 System -> 1900 UDP
2316 -> 4500 UDP


2.txt
Process Port Proto Path
-> 135 TCP
System -> 139 TCP
System -> 445 TCP
-> 1032 TCP
ccApp -> 1045 TCP C:\Program Files\Common Files\Symantec Shared\ccApp.exe
Sticky32 -> 3023 TCP C:\Program Files\Magic Notes\Sticky32.exe
System -> 4285 TCP
System -> 4287 TCP
System -> 4289 TCP
System -> 4291 TCP
System -> 4293 TCP
System -> 4295 TCP
System -> 4298 TCP

System -> 123 UDP
ccApp -> 123 UDP C:\Program Files\Common Files\Symantec Shared\ccApp.exe
System -> 137 UDP
System -> 138 UDP
-> 445 UDP
System -> 500 UDP
Sticky32 -> 1025 UDP C:\Program Files\Magic Notes\Sticky32.exe
System -> 1026 UDP
System -> 1040 UDP
System -> 1900 UDP
-> 4500 UDP



如何把1.txt中的pid那几列去掉，生成2.txt那样的文件，请高手指教

这个问题简单，请楼主养成搜索的习惯，请理解我们的精力实在有限，不可能每个问题都进行解答，特别是这种已问过n+m次的问题。

我觉得楼主在论坛看看关于 for 的帖子就可以自己搞定了。

试试GNU的cut.exe行不行

cut -c7-100 1.txt>2.txt

UnxUtils
http://upload.cn-dos.net/img/377.zip

[ Last edited by HAT on 2008-5-22 at 08:40 PM ]