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@echo off&cls chcp 437>nul&graftabl 936>nul for /f "delims=: tokens=1" %%i in ('findstr /i /n "^:writepass$" "%~f0"') do set line=%%i <"%~f0" more +%line%|debug>nul set "ps=" set n=0 set /p=请输入密码:<nul :start if %n%==256 ( echo &&goto e ) else ( for /f "delims=" %%i in ('password.com') do ( if "%%i"=="?" goto e set "q=%%i" if "%%i" equ "?" (call :p "%%i") else ( if "%%i" lss "? " (GOTO :start) set /p=*<nul set /a n+=1 if "%%i" geq "? " call set "ps=%%ps%%%%q:~1%%" ))) goto start :p if not "%ps%" equ "" ( set "ps=%ps:~0,-1%" SET /p= <nul ) GOTO :eof :e :::Here you can do what you wanna do::: echo. echo 密码为:"%ps%" del password.com pause>nul goto :eof ::下面的请不要随意修改:: :writepass A MOV DX,111 MOV AH,09 INT 21 MOV AH,01 INT 21 MOV AH,4C INT 21 INT 20 DB '?'24 0D 0A 1A R CX 108 N password.com W Q
set /p=*<nul set /a n+=1
set "ps=%ps:~0,-1%" SET /p= <nul
Originally posted by bjsh at 2007-5-2 11:02: set /p的用法: set /p 变量=提示字符串: 在控制台输出提示字符串;把用户的输入(以回车结束)赋值给变量;注意用户的输入在同一行; 他这个自身的特性就决定可以不换行; <nul是把空字符串赋值给变量从而屏蔽了用户的输入;因此看起来似乎只是把提示字符串显示在控制台上而不要求用户输入;同时注意此时没有回车符传递过去;因此不会换行; 这种情况下可以省略变量.. 简写为set /p=提示字符串<nul