中国DOS联盟

比如说这段批处理

@echo off

setlocal enabledelayedexpansion

for /f "delims=-" %%a in (20.txt) do (

set a=%%a

if "!a:~5,6!"=="" echo !a!

)

endlocal

%%a都是数字..我想知道123456 654321这样的``我想显示出少于6位的数字..怎么写呢``?

Last edited by bjsh on 2007-7-31 at 10:15 AM ]

变量截取.

能指点一下不..我没想到哪个命令实现``

显示少于6位的数字？
借鉴3742668 荣誉版主 的代码

@echo off

setlocal enabledelayedexpansion

for /f "delims=-" %%a in (a.txt) do (

 set str=

 for /l %%i in (1 1 6) do (

 set str=!str!.

 echo %%a|findstr /x !str!

)

)

pause

考虑到效率问题，觉得还是建立一个临时文件比较快。

@echo off

setlocal ENABLEDELAYEDEXPANSION

rem for /f "delims=-" %%a in (20.txt) do echo %%a>>a.txt

for /l %%a in (1 1 3) do (

    for /l %%i in (1,1,%%a) do (

        set str=!str!.

        findstr /x !str! a.txt

    )

)

pause>nul

Last edited by 26933062 on 2007-8-15 at 02:59 AM ]

@echo off

setlocal ENABLEDELAYEDEXPANSION

for /f "delims=" %%a in (20.txt) do (

set str=%%a

set str1=!str:~6,1!

if not defined str1 echo %%a

)

pause

这样可以不？

@echo off
setlocal enabledelayedexpansion
for /f "delims=-" %%a in (20.txt) do (
if !a! LSS 10000 echo !a!
set a=
)
endlocal

Originally posted by knoppix7 at 2007-8-15 13:41:
这样可以不？

@echo off
setlocal enabledelayedexpansion
for /f "delims=-" %%a in (20.txt) do (
if !a! LSS 10000 echo !a!
set a=
)
endlocal

可以可以 似乎更简单
@echo off
setlocal enabledelayedexpansion
for /f %%a in (20.txt) do (
set a=%%a
if !a! LSS 1000000 echo !a! >>21.txt
)
pause

谢谢了。

@echo off
for /f %%a in (d:\test\123456\123456.txt) do (
if %%a LSS 1000000 echo %%a >>21.txt
)

受教。