中国DOS联盟

如何把一个文件的第3行——第90行的内容找出来，并传递给新的*.txt文件！谢谢！

skip 2行，读一次>new.txt

skip 89行，读一次>>new.txt

我好像写过，找不着了

4楼能解释下代码吗？

@echo off

for /f "skip=2 delims=" %%i in (1.txt) do (
@echo %%i>>Out.txt
goto Next
)
:Next
for /f "skip=89 delims=" %%i in (1.txt) do (
@echo %%i>>Out.txt
goto Exit
)
:Exit
pause>nul


还是觉得自己的这种好……如果行数比较多上面的FINDSTR要把文本都加上行数……再过滤……

如果楼主是要第3行到第90行的内容的话可以这样

@echo off
for /l %%a in (3,1,90) do call :need %%a
:need
for /f "tokens=1* delims=:" %%i in ('findstr /n . 1.txt') do if %%i==%1 echo %%j>>2.txt

for /f "delims=: tokens=1*" %%a in ('findstr/n .* test.txt') do @(if %%a equ 3 (echo\%%b) else (if %%a equ 90 echo\%%b))>>ok.txt

[ Last edited by lxmxn on 2007-4-27 at 10:38 AM ]

原格式输出，不能输出空行
@echo off for /l %%n in (3,1,90) do call :need %%n pause exit :need set /a line=%1-1 for /f "skip=%line% delims=" %%i in ('more test.txt') do ( echo %%i goto :eof )

可以输出空行，但每行不能含有和行号相同的“行号:”字符，不能输出“!、:”字符及同行中“!、:”字符包围的字符
@echo off setlocal EnableDelayedExpansion for /l %%n in (31,90) do call :need %%n pause exit :need set /a line=%1-1 for /f "skip=%line% delims=" %%i in ('findstr /n .* "test.txt"') do ( set "str=%%i" set "str=!str:%1:=!" if not "!str!" == "" (echo !str!) else echo. goto :eof )

[ Last edited by zh159 on 2007-4-27 at 10:49 AM ]

sed "3,90!d" life