wmic process get processid,executablepath
以上两项输出自定义processid为第一列,executablepath为第二列,可否?
@echo off
::view connection by:everest@cn-dos.net
::!executablepath-expand-LO!set adv= wmicprocess where handle="%dtp%" get executablepath|find /v /i "executablepath"
:top
ECHO Simple Netstat 网络连接查看器 timeon:%time:~0,-3%
ECHO --------------------------------------------------------------------------------
ECHO 本机地址/端口 远程地址/端口 连接状态 进程 进程名称
for /f "skip=4 tokens=*" %%i in ('netstat -abn') do (
set nh=%%i x
call set nha=%%nh:]=%%
echo %%i|findstr /b "
不满足的是没有一个简单快捷的方法获取进程完整路径
大家新年好
[ Last edited by everest79 on 2007-2-27 at 09:57 PM ]
