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for /f "delims=" %%i in (l.txt) do (set/a num+=1)

echo len=%num%

But if there are carriage return symbols in the line, the result will be incorrect. How to modify it, thanks!

See if you need blank lines and lines starting with ;

All need. As long as there are characters in a line, no matter what characters they are. Including lines with only one carriage return character.

Last edited by scriptor on 2007-2-25 at 09:42 PM ]

Originally posted by scriptor at 2007-2-26 09:57:
All are required. As long as there are characters in a line, no matter what characters they are. Including lines with only a carriage return character.

Last edited by scriptor on 2007-2-25 at 09:42 PM ]

Then still use sed. sed -n $= life. Because when there are blank lines in the file, using findstr /N . life will still ignore blank lines.

The content of my l.txt is:
w

e
The content of my bat file is:
@echo off
for /f "delims=" %%i in ('find /v /i /n "" l.txt') do (set/a num+=1)
echo len=%num%
pause>nul

The result is 4, but there are only three lines??
Does it have to be subtracted by 1 like this to be correct? What's the reason for this?
Are there other methods?

You mean using VBS or JS?

Of course that's possible. But what I want is bat.

@echo off
setlocal enabledelayedexpansion
set i=0
for /f %%a in (1.txt) do (
set /a i+=1
echo !i! %%a >>1new.txt
)

Cannot include blank lines! :(

Last edited by xycoordinate on 2007-2-26 at 10:10 AM ]

@ECHO %DBG% OFF & SETLOCAL ENABLEDELAYEDEXPANSION



FOR /F %%i IN ('findstr /n . l.txt') DO SET /A LEN=%%i 2>nul

ECHO %LEN%

Brother Scriptor,

Here's a weird method!! Haha, take advantage of a small bug in SET /A.

@ECHO %DBG% OFF & SETLOCAL ENABLEDELAYEDEXPANSION



FOR /F %%i IN ('findstr /n . l.txt') DO SET /A LEN=%%i 2>nul

ECHO %LEN%

@echo off

for /f "tokens=1 delims=:" %%a in ('findstr /n .* 1.txt') do set a=%%a

echo The length of file 1.txt is %a%

pause&exit/b0

It can handle blank lines and lines containing other characters:

@echo off

for /f "tokens=1 delims=:" %%a in ('findstr /n .* 1.txt') do set a=%%a

echo The length of file 1.txt is %a%

pause&exit/b0

@echo off

FOR /F "delims=:" %%i IN ('findstr /n . a.txt') DO SET LEN=%%i

ECHO %LEN%

pause

The effect of floor 10 is the same as:

@echo off

FOR /F "delims=:" %%i IN ('findstr /n . a.txt') DO SET LEN=%%i

ECHO %LEN%

pause

It uses set/a to remove the ":" character after the number.

SET LEN=%%i: Set LEN equal to the number of lines displayed by findstr /n (no need to count), including all lines

Last edited by zh159 on 2007-2-26 at 11:04 AM ]

Originally posted by zh159 at 2007-2-27 00:02:
The effect of floor 10 is the same as:

@echo off

FOR /F "delims=:" %%i IN ('findstr /n . a.txt') DO SET LEN=%%i

ECHO %LEN%

pause

It uses set/a to remove the ":" character after the number.
SET LEN=%%i: Set LEN equal to the number of lines displayed by findstr /n (without counting), including all lines

For floor 10, mainly used 2>nul, wonderful!!!

Last edited by xycoordinate on 2007-5-5 at 10:49 AM ]

look!
<a href="http://www.cn-dos.net/forum/viewthread.php?tid=33878&fpage=1&highlight=%E8%A1%8C%E6%95%B0" target="_blank">How to determine the number of lines in a text in batch processing</a>

Don't understand? Why is it much slower than
find /v /c "" 1.txt>cs.txt
for /f "tokens=2 delims=:" %%i in (cs.txt) do @echo %%i