中国DOS联盟

实例如下：
@echo off & set VAL=10& set Z=VAL
echo %Z%
echo %%Z%%
echo %%%Z%%%
echo %%%%Z%%%%
echo %%%%%Z%%%%%
call echo %Z%
call echo %%Z%%
call echo %%%Z%%%
call echo %%%%Z%%%%
call echo %%%%%Z%%%%%


gives the following output (only the line 'call echo %%%Z%%%' gives me what
I originally wanted): -


VAL
%Z%
%VAL%
%%Z%%
%%VAL%%
VAL
VAL
10
%Z%
%VAL%


And running the echo commands from test.bat at the command prompt gives: -


VAL
%VAL%
%%VAL%%
%%%VAL%%%
%%%%VAL%%%%
VAL
10
%10%
%%10%%
%%%10%%%


现在想问的问题是：在用CALL调用内部命令ECHO的时候要脱掉一个%符号，但是echo命令在显示%符号的时候是双%%显示为单%，4个%显示为双%，想问一下两者先考虑哪个？也就是说是先执行call的脱掉%字符？还是先脱掉echo显示%符号的脱掉，从以上实例可以看出先是脱掉ECHO进行显示的%符号脱掉，呵呵，大家细细琢磨吧，很绕人的，^_^.........

[ Last edited by bagpipe on 2006-8-21 at 15:51 ]