中国DOS联盟

You say you are a sock puppet =。=

@echo off&setlocal enabledelayedexpansion
set "str=ab"&set /a a=%random%%%60+1
:begin
set /a b=%random%%%2
set c=!str:~%b%,1!&set var=%var%!c!
set /a n+=1
if %n% lss %a% goto begin
echo 下面为本次生成的字符串：
echo %var%
set "str="&set n=0
:lp
if !n! lss 60 if defined var (
   set /a b=%random%%%2
   if !b! equ 0 (
      set "b= "
      ) else (
      set b=!var:~,1!&set /a n+=1
   )
   set str=%str%!b!
   set var=%var:~1%
   goto lp
)
echo.%str%
if !n! lss 60 set var=%str%&set str=&goto lp
pause>nul

Originally posted by 26933062 at 2008-5-7 19:44:
Reply to post 12
Sorry, the answer is still incorrect. Maybe I didn't describe it clearly enough.
The space cannot be directly above each letter.
Let me put it this way
Randomly generate the first letter. For example, if it is a, then...

It's not difficult to do this. You can slightly modify my code in post 12 to achieve it, but the difficulty is that it will then be difficult to meet the requirement of a total of 60 characters. For example, when there is only one a in the first line, the code is as follows:

@echo off&setlocal enabledelayedexpansion
set "str=ab"&set /a a=%random%%%60+1
:begin
set /a b=%random%%%2
set c=!str:~%b%,1!&set var=%var%!c!
set /a n+=1
if %n% lss %a% goto begin
echo The following is the generated string for this time:
echo %var%
set "str="&set n=0
:lp
if !n! lss 60 if defined var (
   set /a b=%random%%%2
   if !b! equ 0 (
      set "b= "
      ) else (
      set b=!var:~,1!&set /a n+=1
   )
   set str=%str%!b!
   set var=%var:~1%
   goto lp
)
echo.%str%
if !n! lss 60 set var=%str%&set str=&goto lp
pause>nul

Hehe, it seems there's a big problem with my description. The number of characters in the first line in the result is never less than that in the second line, and the number of characters in the second line is never less than that in the third line...

To be honest, I'm really confused by you. Why don't you, brother, write out the code!

Is it really that hard to understand? To be honest, you should know it by looking at the sample in the top post. It's just that the total number of a and b is set to 60. Which of the codes written by brother zw19750516 outputs the format of the top post?

That's because I didn't understand it well. Just please brother write out the code to take a look!

abababababababababa
xbxbxxabaxxbaxxxa
xbxxxxaxaxxbaxxxx
xxxxxxaxaxxbaxxxx
xxxxxxxxaxxbxxxxx
xxxxxxxxxxxbxxxxx

x represents a space. For example, the second character in the first line is b, but in the fourth line, the second character becomes a space... In the fifth line, the second character must also be a space. If it becomes a space in the third line, then in subsequent lines, the second position must also be a space. I wonder if you can understand what I'm saying~~^_^

Misunderstood and deleted the post

Last edited by terse on 2008-5-7 at 11:10 PM ]

Originally posted by pusofalse at 2008-5-7 22:21:
ababababababababa
xbxbxxabaxxbaxxxa
xbxxxxaxaxxbaxxxx
xxxxxxaxaxxbaxxxx
xxxxxxxxaxxbxxxxx
xxxxxxxxxxxbxxxxx

x represents a space
For example, the 2nd character of the first line is b, and by the fourth line, the 2nd character...

If it is like this, please run my code of 17.

Hope to change to a 90s way of thinking... The problem will be simpler...

Originally posted by zw19750516 at 2008-5-7 10:24 PM:

If that's the case, please run my code at 17.

Hmm, if there is no limit on the number of elements, indeed it is like this... But I'm really sorry~ I just forgot to mention again that the sum of the number of a and b should be equal to 60.

The perseverance and research spirit of all the seniors are really admirable!

&&Then I can only say that there is a problem with this question. It is very difficult to meet the three conditions of randomly generating strings, decreasing output, and the total number of output characters (excluding the original string and spaces) being 60.
　　This depends on the first point: whether the number of characters in the originally generated string is large. For example, if the originally generated string has only one character, see who can ensure that no spaces are generated in the next 59 lines.
　　Also depends on the second point: whether the number of spaces generated in each line is large. If more than 30 spaces are generated in the first line, it is恐怕 difficult to maintain the condition that the total number of output characters is 60.

Reply to post 23: terse

Your code is also incorrect. It's impossible to have duplicate letters horizontally in each row, like "bb" or "aa". It should be "abababab" or "bababa". Also, your code seems to display many redundant blank lines.

The total number of "a" and "b" is 60, but which positions are "a" and which are "b" is random.

However, adjacent left and right cannot be repeated, like "bb" is not allowed, unless it's "b space b", but the first row cannot have spaces. And all vertical rows must be the same.

The person who tied the bell on the tiger must take it off.... Go to Batch Processing Home to have a look, but it seems that the source code hasn't been provided yet. The moderators there are also extremely powerful, just that they don't have time to surf the Internet.

Algorithm problem... I think the experts in the forum should still be able to solve it.

a and b total 60? The output you provided seems insufficient?