I successfully made a DOS bootable USB drive using a USB flash drive, and I successfully automatically started GRUB through autoexec.bat. But the root directory is a bit too messy. I newly created a directory BOOT and put all the main GRUB program and IMG files into BOOT. But now I can't start GRUB when booting, and I can only start GRUB by entering commands. I once found a command in the forum that I could add to autoexec.bat, but I lost it. Can someone give me a new command so that the USB drive can automatically enter the GRUB menu after booting?
The original AUTOEXE only had one sentence "GRUB". After I moved the GRUB main program to the BOOT folder, I added the path "/BOOT/GRUB" inside, but it still didn't work. I couldn't enter the GRUB main menu when booting, which means GRUB didn't start. How should I change this command to make GRUB execute automatically when booting?
[ Last edited by zrn0681 on 2010-11-30 at 12:56 ]
The original AUTOEXE only had one sentence "GRUB". After I moved the GRUB main program to the BOOT folder, I added the path "/BOOT/GRUB" inside, but it still didn't work. I couldn't enter the GRUB main menu when booting, which means GRUB didn't start. How should I change this command to make GRUB execute automatically when booting?
[ Last edited by zrn0681 on 2010-11-30 at 12:56 ]
