China DOS Union

-- Unite DOS · Advance DOS · Grow DOS --
Union site: www.cn-dos.net　Forum site: www.cn-dos.net/forum

中国DOS联盟论坛
The time now is 2026-10-02 09:40

47,813 topics / 349,918 posts / today 0 new / 48,279 members

DOS批处理 & 脚本技术（批处理室） » Question: how to filter out percent signs on the command line

Floor1　kuixuan	Posted 2010-07-01 15:49
新手上路　Posts 2　Credits 2
@echo off set abc=123 set /p xx=enter: set "xx=%xx:"=%" echo %xx% pause The meaning of the code 【set "xx=%xx:"=%"】 is to filter out the 【quotation marks】 If you enter at : %abc% the execution result of the code is to display —— But now I need to filter out the 【percent signs】 That is, I want the execution result to become displaying on the screen, in other words, the percent signs in the previously entered line %abc% are deleted So I modified the code like this —— set "xx=%xx:%=%" But it gave an error, so how should I do it to filter out the 【percent signs】 I hope everyone can help me, thanks [ Last edited by kuixuan on 2010-7-1 at 15:58 ]

Floor2　Lin7uan	Posted 2010-07-02 01:00
初级用户　Posts 32　Credits 38
I'm a newbie too. Could you explain in more detail set "xx=%xx:"=%" this line?

Floor3　HAT	Posted 2010-07-02 13:09
版主　Posts 5,017　Credits 9,023
String replacement feature of the set command

Floor4　pdanniel66	Posted 2010-07-03 05:19
初级用户　Posts 64　Credits 68
Test1 : @echo off set abc=123 set /p xx=enter: set "xx=%xx:"=%" echo %xx% pause The execution result is as follows: enter:"aa aa Press any key to continue . . . Test2 : @echo off set abc=123 set /p xx=enter: set "xx=%xx:(=%" echo %xx% pause The execution result is as follows: enter: (aa aa Press any key to continue . . .

Floor5　kuixuan	Posted 2010-07-03 23:46
新手上路　Posts 2　Credits 2
Seems like this has turned into a tutorial thread, but does nobody know how either?