China DOS Union

@echo off
set abc=123
set /p xx=enter:
set "xx=%xx:"=%"
echo %xx%
pause

The meaning of the code 【set "xx=%xx:"=%"】 is to filter out the 【quotation marks】
If you enter at : %abc%
the execution result of the code is to display ——

But now I need to filter out the 【percent signs】

That is, I want the execution result to become displaying on the screen, in other words, the percent signs in the previously entered line %abc% are deleted

So I modified the code like this —— set "xx=%xx:%=%"

But it gave an error, so how should I do it to filter out the 【percent signs】

I hope everyone can help me, thanks

[ Last edited by kuixuan on 2010-7-1 at 15:58 ]

I'm a newbie too. Could you explain in more detail
set "xx=%xx:"=%"
this line?

String replacement feature of the set command

Test1 :
@echo off
set abc=123
set /p xx=enter:
set "xx=%xx:"=%"
echo %xx%
pause
The execution result is as follows:
enter:"aa
aa
Press any key to continue . . .
Test2 :
@echo off
set abc=123
set /p xx=enter:
set "xx=%xx:(=%"
echo %xx%
pause

The execution result is as follows:
enter: (aa
aa
Press any key to continue . . .

Seems like this has turned into a tutorial thread, but does nobody know how either?