China DOS Union

The title is to transfer the data in buff1 to buff2. The source program is as follows:

DSEG SEGMENT
buff1 db 0,1,2,3,4,5,6,7,8,9,
db 11,12,13,14,15,16,17,18,19,20
buff2 db 20 dup(?)

DSEG ENDS


CSEG SEGMENT
assume cs:CSEG, ds:DSEG



MAIN PROC FAR ;Main program entry

mov ax, dseg
mov ds, ax
mov ax,eseg
mov es, ax
mov cx,20
lea si,buff1
lea di,buff2
cycle:mov al,
mov ,al
inc si
inc di
loop cycle
mov ax, 4c00h ;Program ends, return to the operating system
int 21h
MAIN ENDP

CSEG ENDS

END MAIN
After compilation
The following error occurs
Unable to open input file: transformdata.asmExperts, please give guidance

The English means: Cannot open input file: transformdata.asm

I used MASM 5.0 to compile, and it prompted a.asm(2): warning A4101: Missing data; zero assumed

And where is eseg in the 18th line of the code.. mov ax,eseg?

Is this format correct? I wrote it like this because it's like that in the book, and when entering tables, it's also written like that in the book. Is it that some versions of MASM don't support it?

As pointed out by building 3, there are 2 errors. Correspondingly, remove the comma at the end of line buff1 and change eseg to dseg. "Cannot open input file: transformdata.asm" indicates that the filename of your source program should not be transformdata.asm, that is, rename it to transformdata.asm, and it will be okay.

The original error was at the end, the problem... I didn't notice this.

Many thanks

Are you also learning assembly?

chrise, why are there no new questions recently... I'm not used to it.

Will it be better to write like this? Moreover, it is not easy to have problems when modifying the data.

DSEG  SEGMENT

      buff1 db 0,1,2,3,4,5,6,7,8,9,11,12,13,14,15,16,17,18,19,20

      datalen equ $-buff1; It is better to use common pseudo-instructions to make the program easier to modify.

      buff2 db datalen dup(?)

DSEG  ENDS

CSEG  SEGMENT

      assume cs:CSEG,ds:DSEG

MAIN  PROC FAR; Main program entry

      mov ax,seg DSEG

      mov ds,ax

      mov es,ax

      cld      

      mov si,offset buff1

      mov di,offset buff2

      mov cx,datalen

      rep movsb; String COPY operation is frequently used in software, so the smaller the loop body, the better.

      mov ax,4c00h; Program ends and returns to the operating system

      int 21h

MAIN ENDP

CSEG ENDS

      END MAIN

[ Last edited by netwinxp on 2010-7-6 at 19:39 ]