China DOS Union

@echo off
echo.%%1^>>11.bat
echo.pause

In the original code, to output the `>` symbol correctly in the echo command, you need to use `^>` to escape it. So the modified code for echoing `%1>` into 11.bat is `echo.%%1^>>11.bat`.

This depends on whether it is a pure DOS environment or a CMD environment. If it is a CMD environment, you only need to add ^ before >. For example:
echo %%1^>>11.bat

And if it is a pure DOS environment, obviously the above method won't work. A relatively simple method is to borrow the prompt $g character escape function. I don't remember the detailed usage very well (because I rarely use it). You can search for old posts before. I remember that willsort once had a post that systematically discussed this problem. There should be a link in the top essence post summary of this version.

[ Last edited by Climbing on 2009-3-19 at 03:09 ]

Never used DOS, but often used under CMD

On the second floor,,
In echo %%1^>11.bat, is there still a > needed in front of the ^?

It has been corrected on the second floor.

Thanks, Climbing was worrying about this problem, and it's solved!

Learning

Not only that, if there is a number following =, such as =3, then ^ must be added before 3, expressed as =^3. Hehe, it's very interesting. Similarly, for %, another % must be added, expressed as %%, to output the correct %.

Seriously, it would be good if someone explained DEBUG. "The problem is it's a bit difficult to learn" I can't understand it.