--output
--projects
--project1
--bin
--debug
project1.dll
project1.xml
--release
project1.dll
project1.xml
--obj
--debug
project1.dll
project1.xml
project1.pda
--release
project1.dll
project1.xml
--project2
--bin
--debug
project1.dll
project2.dll
project2.xml
--obj
--debug
project1.dll
project1.xml
project1.pda
..............
The output folder and the projects folder are at the same level. Inside the projects folder there are multiple project folders . Each project folder has a bin folder and an obj folder, and inside the bin folder and obj folder there are debug and release folders. Now I want to copy the contents of the debug folder inside the bin folder into output, but not the ones in obj. Also, because project2 also has a file called project1.dll, I need to skip that file. This batch file is too hard for me. Please give me a hand.
[ Last edited by iipiip on 2008-9-4 at 04:14 PM ]
--projects
--project1
--bin
--debug
project1.dll
project1.xml
--release
project1.dll
project1.xml
--obj
--debug
project1.dll
project1.xml
project1.pda
--release
project1.dll
project1.xml
--project2
--bin
--debug
project1.dll
project2.dll
project2.xml
--obj
--debug
project1.dll
project1.xml
project1.pda
..............
The output folder and the projects folder are at the same level. Inside the projects folder there are multiple project folders . Each project folder has a bin folder and an obj folder, and inside the bin folder and obj folder there are debug and release folders. Now I want to copy the contents of the debug folder inside the bin folder into output, but not the ones in obj. Also, because project2 also has a file called project1.dll, I need to skip that file. This batch file is too hard for me. Please give me a hand.
[ Last edited by iipiip on 2008-9-4 at 04:14 PM ]

