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DOS批处理 & 脚本技术（批处理室） » [Help] Question about splitting with "delims=="?

Floor1　terrytong	Posted 2008-07-30 11:22
中级用户　Posts 115　Credits 240
set /f "delims==" %a in ('set') do echo %a will display the content before the = sign. But if I want to get the characters after the = sign, then what? Experts, please teach me.

Floor3　terrytong	Posted 2008-07-30 13:27
中级用户　Posts 115　Credits 240
Originally posted by HAT at 2008-7-30 12:20: for /f "delims==" %a in ('set') do echo %b I tried it, but it doesn't work. It just displays %b.

Floor4　yishanju	Posted 2008-07-30 13:29
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You probably need to add tokens.

Floor6　terrytong	Posted 2008-07-30 13:47
中级用户　Posts 115　Credits 240
Originally posted by HAT at 2008-7-30 13:34: for /f "tokens=1,2 delims==" %a in ('set') do echo %b It works now, thanks HAT. Can you help explain it to me? Why does adding tokens=1,2 make it take the right side instead? But adding tokens=1 doesn't work. Thanks.

Floor7　HAT	Posted 2008-07-30 14:51
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tokens=1 means only taking the first column; at that point only %a is valid.

Floor8　yishanju	Posted 2008-07-31 18:40
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Actually... after for /? there is a line like this, FOR /F "usebackq delims==" %i IN (`set`) DO @echo %i I only just noticed it myself