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DOS批处理 & 脚本技术（批处理室） » [Help] Calculate the size of each directory

Floor1　lfzzj	Posted 2008-07-29 17:53
初级用户　Posts 56　Credits 159
There are many directories inside d:\aaa on my computer, for example 111 222 333, and inside each directory there are many subdirectories and files. I want to calculate the sizes of these directories like 111 222 333. How should I write it?

Floor2　bat-zw	Posted 2008-07-30 01:06
金牌会员　Posts 1,276　Credits 3,105
@echo off&setlocal enabledelayedexpansion for /f "delims=" %%a in ('dir /ad /b "d:\aaa"') do ( for /f "delims=" %%i in ('dir /s /a-d/b "%%a\."') do set /a n+=%%~zi echo total file size in %%a is !n! bytes 　 set "n=0" ) pause>nul [ Last edited by bat-zw on 2008-7-30 at 01:13 AM ]

Floor3　lfzzj	Posted 2008-07-30 12:43
初级用户　Posts 56　Credits 159
Thank you very much, I learned quite a lot.

Floor4　zhoumeng	Posted 2008-07-31 09:43
初级用户　Posts 7　Credits 34
Why didn't I think of that? For a single directory, size is a whole. For a large directory, then the sizes of the small directories inside can be calculated. But could you modify it so the unit is KB, and put a comma every three digits?

Floor5　pusofalse	Posted 2008-08-03 02:05
银牌会员　Posts 646　Credits 1,604
@echo off&setlocal enabledelayedexpansion for /r /d %%a in () do ( for %%i in ("%%a\.*") do set/a n+=%%~zi set/a kb=n/1024 call :lp "%%a" echo.&set n=0 ) pause>nul&exit/b :lp if defined kb ( set var=,!kb:~-3! set size=!var!!size! set kb=!kb:~,-3! goto lp ) set size=!size:~1! echo about !size!KB in %~1 set size= Converted to KB.