China DOS Union

@echo off
for /f "tokens=3,5,7,8 delims==/> " %%i in ('findstr "FACTORY DUT" 1.txt^|findstr /v "FIXTURE"') do call :lp %%i %%j %%k %%l
pause>nul&goto :eof
:lp
set str=%1
if defined str echo %str:~1,-1%
if defined str shift&goto lp

Thanks, and experts are also welcome to chime in.

Sheesh, why does everyone want an explanation.
What comes before :lp is using suitable delimiters and a for+findstr statement to grab the wanted strings from 1.txt, so I won't explain that in detail.
I believe newbies may have a bit of trouble understanding the shift statement after the :lp label. Actually, if you just type shift /? in cmd, you can get a basic idea that what shift does is shift the parameters after call. And here shift is doing the same thing: first, four parameters are passed over from the for statement, namely %%i %%j %%k %%l, that is, %1 %2 %3 %4. Each time lp loops once, shift moves the parameters one place back. The first time, the parameter is %1=%%i, but the second time %1 moves to the second position, so now %1=%%j, and this continues until %1 has been shifted to the position of the last parameter.

[ Last edited by zw19750516 on 2008-6-20 at 06:34 PM ]