About backtracking to any time - China DOS Union Forum - China DOS Union

&&Because of a brother's help request, I suddenly thought of writing a batch script (not using VBS) for arbitrary time backtracking. Because I knew that judging the time points of hours, minutes, days, months, and years would be quite complicated, I was mentally prepared at the beginning, but only when I was in the middle of writing did I really understand the difficulties here. The difficulty lies in how to convert and calculate the arbitrary time entered by others. For example, if you enter 0 0 0 0 100000 (meaning 100,000 minutes), how to convert it into the year, month, day, hour, and minute to backtrack. I racked my brains and still couldn't figure it out clearly. I hope everyone can sort out the ideas. Because the meaning of the problem is also difficult to describe clearly, I specially post my partial code below:


@echo off&color 1f&mode con lines=10&setlocal enabledelayedexpansion
title ***Time Backtracking Batch Script*** by cn-dos zw19750516
:begin
cls&echo.&echo ===============================================================================
echo Please enter the time to backtrack. Please enter it correctly in the format of year month day hour minute. If there is no value, please enter 0. Separate them with spaces in between. Do not pad 0 in front of the value. For example: 10 6 1 19 44 (10 years, 6 months, 1 day, 19 hours, 44 minutes), 0 0 0 0 400 (400 minutes). And 10 06 01 19 44 and 10 6 and 10 6 0 0 0 0 are all incorrect inputs.
echo ===============================================================================
echo.&set /p times=Please enter here:
echo %times: =%|findstr ""&&goto wrong
for %%i in (%times%) do (
    set /a n+=1&set str=%%i
    if "!str:~,1!" equ "0" goto wrong
)
if !n! neq 5 goto wrong
set n=0
for /f "tokens=1-5 delims= " %%a in ("%times%") do set /a ys=%%a,ms=%%b,ds=%%c,hs=%%d,mis=%%e
set /a y=%date:~,4%,m=100%date:~5,2%%%100,d=100%date:~8,2%%%100,mi=100%time:~3,2%%%100
if "%time:~,1%"=="" (set h=%time:~1,1%) else (set h=%time:~,2%)
set /a a=%y%%%4,b=%y%%%100,c=%y%%%400
if %c% equ 0 (set yun=A) else (if %a% equ 0 if %b% neq 0 set yun=A) 
if defined yun (set n=29) else (set n=28)
set /a mi-=mis,h-=hs,d-=ds,m-=ms,h-=hs
............................
:wrong
cls&echo.&echo.&echo Incorrect value. Please enter correctly&ping /n 2 127.1>nul&goto begin

[ Last edited by zw19750516 on 2008-6-2 at 12:39 AM ]

My algorithm for this kind of problem is: first convert any given date into minutes (and if needed, also convert to seconds, hours, days), and then convert the minutes back into a date. You can refer to the functions in the function library --- timediff

In fact, there are classic codes in the forum for backtracking days. Just judge the number of days in the time part.

Brothers, is it too simple? I've read all the forum-related posts and also discussed with namejm on QQ.

In fact, my original intention was to write a batch processing program for arbitrary time backtracking. As long as others input any set of five values in the input format of year, month, day, hour, and minute, they can get the backtracked year, month, day, hour, and minute. For example, input 0 0 0 100000 0 (100000 hours).

Request zw19750516 brother to disclose his QQ number and namejm's QQ number ^_^

Provide an idea: First, convert the month, day, and time into the number of days. Then subtract the input year from the current year. Then subtract the converted number of days from the result. Finally, refine the time precisely.

Originally posted by 26933062 at 2008-6-1 22:37:
Provide an idea
First, convert the month, day, time into days.
Then subtract the input year from the current year,
Then subtract the converted days from the result, and finally refine the time.

Thanks for your concern many times, brother. Please look at this set of values 20 34 600 4000 10000, going back 20 years, 34 months, 600 days, 4000 hours, 10000 minutes. I have an idea that is to calculate the time difference from the current system time to January 1, 00:00 of the first year of the AD as the number of minutes, then convert all the input time into the value counted in minutes, then subtract the input converted value from the system value, and then push forward the year, month, day, hour, minute from the reference value of January 1, 00:00 of the first year of the AD. The problem is that it is quite difficult to convert the input value into minutes. For example, how many minutes is 20 years =? and 34 months =?

Passing by...

Still VBS is refreshing~~

It really feels so difficult. Could it really be that batch processing can't solve this problem?

Will it overflow
Also, why do I always get an error when running the above
What is the role of this P

If all are converted into minutes, it will be an extremely large number, and then it involves the problem of large number calculation.

In addition, there is another question: 20 years, 2 months, 600 days, 4000 hours, 10000 minutes

As above, what does 2 months refer to? For example, if today is June 1st, is 2 months ago April 1st?

Or 2 months after the current time minus 600 days, 4000 hours, 10000 minutes?

Originally posted by 26933062 at 2008-6-1 23:11:
If all are converted to minutes, it will be an extremely large number, which then involves the problem of large number calculation.
In addition, there is another question: 20 years, 2 months, 600 days, 4000 hours, 10000 minutes
As above, what does 2 months refer to...

The five values 20, 34, 600, 4000, 10000 are all to be deduced through calculation, not simply subtraction of the same phase

If all are converted into minutes, it will be an extremely large number, which then involves the problem of large number calculation.
In addition, there is another question: 20 years, 2 months, 600 days, 4000 hours, 10000 minutes
As above, what does 2 months refer to? For example, if today is June 1st, is 2 months ago April 1st?
Or is it 2 months after subtracting 600 days, 4000 hours, and 10000 minutes from the current time?

I think the building owner means: 20 years + 2 months + 600 days + 4000 hours + 10000 minutes

But it feels meaningless, and even............. alas

Floor1　bat-zw	Posted 2008-06-01 21:58
金牌会员　Posts 1,276　Credits 3,105
&&Because of a brother's help request, I suddenly thought of writing a batch script (not using VBS) for arbitrary time backtracking. Because I knew that judging the time points of hours, minutes, days, months, and years would be quite complicated, I was mentally prepared at the beginning, but only when I was in the middle of writing did I really understand the difficulties here. The difficulty lies in how to convert and calculate the arbitrary time entered by others. For example, if you enter 0 0 0 0 100000 (meaning 100,000 minutes), how to convert it into the year, month, day, hour, and minute to backtrack. I racked my brains and still couldn't figure it out clearly. I hope everyone can sort out the ideas. Because the meaning of the problem is also difficult to describe clearly, I specially post my partial code below: @echo off&color 1f&mode con lines=10&setlocal enabledelayedexpansion title *Time Backtracking Batch Script* by cn-dos zw19750516 :begin cls&echo.&echo =============================================================================== echo Please enter the time to backtrack. Please enter it correctly in the format of year month day hour minute. If there is no value, please enter 0. Separate them with spaces in between. Do not pad 0 in front of the value. For example: 10 6 1 19 44 (10 years, 6 months, 1 day, 19 hours, 44 minutes), 0 0 0 0 400 (400 minutes). And 10 06 01 19 44 and 10 6 and 10 6 0 0 0 0 are all incorrect inputs. echo =============================================================================== echo.&set /p times=Please enter here: echo %times: =%\|findstr ""&&goto wrong for %%i in (%times%) do ( set /a n+=1&set str=%%i if "!str:~,1!" equ "0" goto wrong ) if !n! neq 5 goto wrong set n=0 for /f "tokens=1-5 delims= " %%a in ("%times%") do set /a ys=%%a,ms=%%b,ds=%%c,hs=%%d,mis=%%e set /a y=%date:~,4%,m=100%date:~5,2%%%100,d=100%date:~8,2%%%100,mi=100%time:~3,2%%%100 if "%time:~,1%"=="" (set h=%time:~1,1%) else (set h=%time:~,2%) set /a a=%y%%%4,b=%y%%%100,c=%y%%%400 if %c% equ 0 (set yun=A) else (if %a% equ 0 if %b% neq 0 set yun=A) if defined yun (set n=29) else (set n=28) set /a mi-=mis,h-=hs,d-=ds,m-=ms,h-=hs ............................ :wrong cls&echo.&echo.&echo Incorrect value. Please enter correctly&ping /n 2 127.1>nul&goto begin [ Last edited by zw19750516 on 2008-6-2 at 12:39 AM ]

Floor3　plp626	Posted 2008-06-01 22:20
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My algorithm for this kind of problem is: first convert any given date into minutes (and if needed, also convert to seconds, hours, days), and then convert the minutes back into a date. You can refer to the functions in the function library --- timediff

Floor4　26933062	Posted 2008-06-01 22:23
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In fact, there are classic codes in the forum for backtracking days. Just judge the number of days in the time part.

Floor5　bat-zw	Posted 2008-06-01 22:28
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Brothers, is it too simple? I've read all the forum-related posts and also discussed with namejm on QQ.

Floor6　bat-zw	Posted 2008-06-01 22:32
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In fact, my original intention was to write a batch processing program for arbitrary time backtracking. As long as others input any set of five values in the input format of year, month, day, hour, and minute, they can get the backtracked year, month, day, hour, and minute. For example, input 0 0 0 100000 0 (100000 hours).

Floor2　bat-zw	Posted 2008-06-01 22:17
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Floor7　HAT	Posted 2008-06-01 22:35
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Request zw19750516 brother to disclose his QQ number and namejm's QQ number ^_^

Floor8　26933062	Posted 2008-06-01 22:37
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Provide an idea: First, convert the month, day, and time into the number of days. Then subtract the input year from the current year. Then subtract the converted number of days from the result. Finally, refine the time precisely.

Floor9　bat-zw	Posted 2008-06-01 22:52
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Originally posted by 26933062 at 2008-6-1 22:37: Provide an idea First, convert the month, day, time into days. Then subtract the input year from the current year, Then subtract the converted days from the result, and finally refine the time. Thanks for your concern many times, brother. Please look at this set of values 20 34 600 4000 10000, going back 20 years, 34 months, 600 days, 4000 hours, 10000 minutes. I have an idea that is to calculate the time difference from the current system time to January 1, 00:00 of the first year of the AD as the number of minutes, then convert all the input time into the value counted in minutes, then subtract the input converted value from the system value, and then push forward the year, month, day, hour, minute from the reference value of January 1, 00:00 of the first year of the AD. The problem is that it is quite difficult to convert the input value into minutes. For example, how many minutes is 20 years =? and 34 months =?

Floor10　slore	Posted 2008-06-01 22:55
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Passing by... Still VBS is refreshing~~

Floor11　bat-zw	Posted 2008-06-01 23:00
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It really feels so difficult. Could it really be that batch processing can't solve this problem?

Floor12　terse	Posted 2008-06-01 23:05
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Will it overflow Also, why do I always get an error when running the above What is the role of this P

Floor13　26933062	Posted 2008-06-01 23:11
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If all are converted into minutes, it will be an extremely large number, and then it involves the problem of large number calculation. In addition, there is another question: 20 years, 2 months, 600 days, 4000 hours, 10000 minutes As above, what does 2 months refer to? For example, if today is June 1st, is 2 months ago April 1st? Or 2 months after the current time minus 600 days, 4000 hours, 10000 minutes?

Floor14　bat-zw	Posted 2008-06-01 23:18
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Originally posted by 26933062 at 2008-6-1 23:11: If all are converted to minutes, it will be an extremely large number, which then involves the problem of large number calculation. In addition, there is another question: 20 years, 2 months, 600 days, 4000 hours, 10000 minutes As above, what does 2 months refer to... The five values 20, 34, 600, 4000, 10000 are all to be deduced through calculation, not simply subtraction of the same phase

Floor15　moniuming	Posted 2008-06-01 23:19
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If all are converted into minutes, it will be an extremely large number, which then involves the problem of large number calculation. In addition, there is another question: 20 years, 2 months, 600 days, 4000 hours, 10000 minutes As above, what does 2 months refer to? For example, if today is June 1st, is 2 months ago April 1st? Or is it 2 months after subtracting 600 days, 4000 hours, and 10000 minutes from the current time? I think the building owner means: 20 years + 2 months + 600 days + 4000 hours + 10000 minutes But it feels meaningless, and even............. alas