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DOS批处理 & 脚本技术（批处理室） » How can echo output [%windir%]?

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Floor1　ceii	Posted 2008-03-11 18:55
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There are the following three statements: @echo [%windir%] @echo [%%windir%%] @echo [%%windir%%]\|sort The result output by the first statement is: [C:\WINDOWS] The result output by the second statement is: [%windir%] The result output by the third statement is: [C:\WINDOWS] I want the third statement to also output: [%windir%]. How should I modify it? (In my actual use, the piped output is not sort, but a third-party tool tr.exe)

Floor2　lxmxn	Posted 2008-03-11 19:01
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Floor3　suntb	Posted 2008-03-11 19:02
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Floor4　pooronce	Posted 2008-03-11 19:03
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Floor5　ceii	Posted 2008-03-11 19:23
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Thanks, everyone. The output result in reply #2 is also [%C:\WINDOWS%], not what I want. Although the result in reply #3 is correct, it doesn't go through a pipe. There are really a lot of methods in reply #4; I'll have to try them slowly.

Floor6　abcd	Posted 2008-03-11 23:57
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Floor7　zcnvnv	Posted 2008-03-12 10:31
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Do you need to make it that complicated? echo [^%windir^%] Completely works

Floor8　abcd	Posted 2008-03-12 11:03
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Originally posted by zcnvnv at 2008-3-12 10:31 AM: Do you need to make it that complicated? echo Completely works What the OP wants is that it must go through sort. Not simply just to display %windir%

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