China DOS Union

```@echo off&setlocal&pushd %tmp% %Hide password by displaying * {s11ss 2007-12-16}%
<"%~f0" more +10|debug>nul&move t "t.com"
echo The length of the password should not bigger than 32!&echo Press any key to continue...&pause>nul&cls
t
echo exit|cmd /kprompt d20:0 20$_q$_|debug>t
for /f "skip=2 tokens=*" %%a in (t) do set t=%%a&call set t=%%t:~61,16%%&call set s=%%s%%%%t%%
for /f "skip=2 tokens=2" %%a in (t) do set/a l=0x%%a&goto :t
:t
cls&echo The password is:&call echo.%%s:~1,%l%%%
del t t.com&popd&echo.&echo Press any key to exit...&pause>nul&goto :eof
e0100 BB 00 B8 8E C3 BF 00 00 BE 00 00 B4 00 CD 16 80
e0110 FC 0E 75 0E 83 FE 00 74 F2 4E 4F 4F 26 C6 05 20
e0120 EB E9 80 FC 1C 74 1C 3C 20 72 E0 26 C6 05 2A 8C
e0130 C2 BB 00 00 8E C3 26 88 84 01 02 8E C2 83 C7 02
e0140 46 EB C8 BB 00 00 8E C3 8B C6 26 A2 00 02 B8 00
e0150 4C CD 21
rcx
53
n t
w
q
```

Assembly?
Can you explain it?

Originally posted by penghuahui at 2007-12-16 11:27 PM:
Assembly?
Can you explain it?

COM file:
For visible characters (including spaces) entered by pressing keys, display an asterisk (*) and simultaneously write the character to the memory address space starting at 0:201h; when the backspace key is pressed, only replace the previous asterisk with a space, and this space may be overwritten by a newly entered visible character next time (if there is no asterisk before pressing the backspace key, do nothing); when the enter key is pressed, end the input process and write the length of the string to 0:200h.

After the batch processing executes the COM file, use debug to write the data from 0:200h to 0:220h to a file, obtain the original input data according to the length of the string and display it.

[ Last edited by s11ss on 2007-12-17 at 09:31 AM ]

How to use it, please boss explain it

Not quite understand, bookmark for later use! Study it slowly when I get started! Thanks to the LZ!

e0100 BB 00 B8 8E C3 BF 00 00 BE 00 00 B4 00 CD 16 80
e0110 FC 0E 75 0E 83 FE 00 74 F2 4E 4F 4F 26 C6 05 20
e0120 EB E9 80 FC 1C 74 1C 3C 20 72 E0 26 C6 05 2A 8C
e0130 C2 BB 00 00 8E C3 26 88 84 01 02 8E C2 83 C7 02
e0140 46 EB C8 BB 00 00 8E C3 8B C6 26 A2 00 02 B8 00
e0150 4C CD 21
Can you ask how it was obtained?