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There is a folder with N files in it. The filenames follow a certain pattern, specifically like this: 00001_20071105_023015_890.txt,00002_20071105_032915_561.txt,.....,00012_20071105_233014_743.txt

Is there any way to get the filename of the one that was created most recently?

Similar questions have already been solved N times, search the forum!!!

Look into the sorting options of the dir command, for example sorting by time.

Originally posted by chenjie9803 at 2007-12-5 16:08:
There is a folder with N files in it. The filenames follow a certain pattern, specifically like this: 00001_20071105_023015_890.txt,00002_20071105_032915_561.txt,.....,00012_20071105_233014_743.txt

Is there any way to get the filename of the one that was created most recently?

I'm a newbie too!
dir *.txt /o:d |find "latest date"

I did search, and there wasn't what I wanted.

Let me state the full requirement: right now there is a program that generates 1 log file every hour, with one folder per day. Now the requirement is to copy each log to the remote server as soon as it is generated.

If that's the case, then a command-line sync tool can completely solve the problem. For example, cmdSync. You only need to use the sync software to periodically synchronize the local log directory to the server through Scheduled Tasks. There's no need to get the latest filename, unless there are stricter or additional requirements.

Right now I'm just thinking about how to do it with a script........

Just getting the latest filename is enough

Do you have to use a script?
I'll just tell you directly then.
A script isn't the simplest solution.
You can try a programming language...