China DOS Union

Little brother, I wrote a batch code that needs to use batch parameters. When testing, I found that some special characters can't be displayed. For example, the following code:
aaa.bat
:::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
@echo off
setlocal EnableDelayedExpansion
set 111=%1
set 222=%2
set 333=%3
echo !111!
echo !222!
echo !333!
:::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
I entered "aaa.bat !a =a ;a", but only 3 a's were displayed, and the preceding symbols! = ; were not displayed. I added escape characters ^ in front of these characters, but it was still 3 a's. Everyone, how can I get these special symbols?

=, ; and several other symbols are treated as separators in parameters;

If you really want to use them as parameters, you can add quotes; and then use %~1 to remove the quotes'

For example, a;ta will be treated as two parameters, a and ta;

! is eaten because variable delay is enabled during set assignment;

You can enable variable delay after the set;

The specific code can be changed to:

@echo off

set 111=%~1

set 222=%~2

set 333=%~3

setlocal EnableDelayedExpansion

echo !111!

echo !222!

echo !333!

aaa.bat "!a" "=a" ";a"

!a
=a
;a

Thanks to the moderator
That is to say, for anything with = and ; characters in the parameters, you need to enclose them in quotes and then remove them in the program
Although this is a bit troublesome, it seems that this is the only way

Also, I want to ask, what is the difference between the delimiter =; and the delimiter space?

There should be no difference anymore.