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Suppose the file test.txt contains purely numerical data, with the following numbers:

25

1

9

385

87

195876

Using the command sort test.txt only gives the following result:

1

195876

25

385

87

9

That is, when sort is used for sorting, it first sorts by the first character. Then if we want to sort according to the usual numerical size, how should we handle it? The expected result should be as follows:

1

9

25

87

385

195876

[ Last edited by suntb on 2007-5-18 at 10:05 AM ]

No one person to help, check the posts in the forum, it seems that sort cannot be realized

[ Last edited by suntb on 2007-5-18 at 11:11 AM ]

I'm also thinking about this question, and there's no answer either

Search more, I remember there was a similar discussion before.

Try the following code:

::code by youxi01@cn-dos.net

::Usage format: In the command line, enter:

:: 

@echo off

setlocal enabledelayedexpansion



if "%2"=="" (

    for /f "tokens=2 delims=#" %%i in ('"%~0" %1 OK^|sort') do echo %%i

) else (

    for /f %%i in (%1) do (

       call :CheckNum %%i Res

       echo !Res!#%%i)

    goto :eof)



pause>nul



:CheckNum num Res

   set/a Res=0

   for /l %%i in (0 1 1000) do (

      set "var=%~1"

      set tmp=!var:~%%i,1!

      if "!tmp!"=="" goto :eof

      set/a Res+=1)

Usage format:
Example: There are numbers in a file named "test.txt" as follows:

25

1

9

385

87

195876

The test result under CMD is as follows:

F:\>paixu.bat test.txt

1

9

25

87

385

195876

But the depressing thing is that when I changed the P processing file name to sort.bat during the test, then the problem came, which made me restart twice, and then I finally understood.....

In the code, the reason for adding the "OK" letters is related to the logic of the `for /f` loop processing. When the code is structured like `"%~0" %1 OK`, it provides additional input content to the script when it is recursively called. The `sort` command then sorts the output, and the `tokens=2 delims=#` is used to extract the second part of the content separated by the `#` delimiter. So the "OK" is just part of the input passed to the script during this recursive and processing flow.

The translated text remains the same as the original code content since it's already in a form that can be presented directly after translation processing:

::code by youxi01@cn-dos.net
::Usage format: In the command line, enter:
::
@echo off
setlocal enabledelayedexpansion

if "%2"=="" (
for /f "tokens=2 delims=#" %%i in ('"%~0" %1 OK^|sort') do echo %%i
) else (
for /f %%i in (%1) do (
call :CheckNum %%i Res
echo !Res!#%%i)
goto :eof)

pause>nul

:CheckNum num Res
set/a Res=0
for /l %%i in (0 1 1000) do (
set "var=%~1"
set tmp=!var:~%%i,1!
if "!tmp!"=="" goto :eof
set/a Res+=1

Why is the "OK" letter added in `for /f "tokens=2 delims=#" %%i in ('"%~0" %1 OK^|sort') do echo %%i`???????

Hehe, how to input this sorting result into a new text file? Please teach me hehe