China DOS Union

There are two for loops. I want to break out of the inner one and return to the outer for loop. What should I do?
Does DOS have anything like break or continue?
The specific code:
@echo off
for /f "delims=" %%i in (1.txt) do call :ss %%i
:ss
set a=%1
setlocal ENABLEDELAYEDEXPANSION
for /f "delims=" %%j in (2.txt) do (
set b=%%j
if !a! NEQ !b! echo %%j>new.txt

Add a statement here to exit the inner for loop

)


Many thanks!

for /f "delims=" %%i in (1.txt) do (
for /f "delims=" %%j in (2.txt) do (
if "%%i" == "%%j" echo %%j>new.txt&&goto :eof
)
)
This seems to work, but for this kind of search, using findstr /G:1.txt 2.txt>>new.txt is a bit more convenient

Thanks

Originally posted by everest79 at 2007-4-26 12:18:
for /f "delims=" %%i in (1.txt) do (
for /f "delims=" %%j in (2.txt) do (
if "%%i" == "%%j" echo %%j>new.txt&&goto :eof
)
)
This seems to work ...

But wouldn't this exit the batch file when %%i equals %%j?

When using a for loop, call another for with call, then use goto :eof inside that for, for example:

@echo off
for /l %%i in (1,1,5) do call :doit %%i
pause
eixt
:doit
for /l %%a in (6,1,10) do (
if "%%a"=="9" goto :eof
echo %1 %%a
)
goto :eof

Posting one more simple example; the rest can be expanded from the above

@echo off
for /l %%a in (6,1,10) do (
if "%%a"=="9" goto :end
echo %1 %%a
)
:end
pause
exit

Thanks

Why is the line echo %1 %%a written like that?? Wouldn't removing %1 make it shorter? I want to know what the advantage of writing it this way is. Please answer, brother dikex.