How can I extract lines 3 through 90 from a file and pass them to a new *.txt file! Thanks!
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中国DOS联盟论坛 » DOS批处理 & 脚本技术（批处理室） » How to extract lines 3 through 90 from a file?
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Original Poster
Posted 2007-04-27 00:59 · 中国 河北 廊坊 霸州市 电信
Floor 2
Posted 2007-04-27 02:03 · 中国 陕西 西安 电信
skip 2 lines, read once >new.txt
skip 89 lines, read once >>new.txt
skip 89 lines, read once >>new.txt
Floor 3
Posted 2007-04-27 02:07 · 中国 广东 广州 天河区 电信
I seem to have written one before, but I can't find it.
Floor 4
Posted 2007-04-27 02:15 · 中国 北京 联通
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| everest79 | +15 | 2007-04-27 02:17 |
Floor 5
Posted 2007-04-27 02:24 · 中国 新疆 乌鲁木齐 天山区 电信
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Could post #4 explain the code?
Floor 6
Posted 2007-04-27 02:32 · 中国 陕西 西安 电信
@echo off
for /f "skip=2 delims=" %%i in (1.txt) do (
@echo %%i>>Out.txt
goto Next
)
:Next
for /f "skip=89 delims=" %%i in (1.txt) do (
@echo %%i>>Out.txt
goto Exit
)
:Exit
pause>nul
I still think my own way is better... If there are a lot of lines, the FINDSTR above has to add line numbers to the whole text... and then filter...
for /f "skip=2 delims=" %%i in (1.txt) do (
@echo %%i>>Out.txt
goto Next
)
:Next
for /f "skip=89 delims=" %%i in (1.txt) do (
@echo %%i>>Out.txt
goto Exit
)
:Exit
pause>nul
I still think my own way is better... If there are a lot of lines, the FINDSTR above has to add line numbers to the whole text... and then filter...
Floor 7
Posted 2007-04-27 06:02 · 中国 上海 浦东新区 电信
If what the OP wants is the content from line 3 to line 90, then you can do it like this
@echo off
for /l %%a in (3,1,90) do call :need %%a
:need
for /f "tokens=1* delims=:" %%i in ('findstr /n . 1.txt') do if %%i==%1 echo %%j>>2.txt
Floor 8
Posted 2007-04-27 12:29 · 中国 湖北 武汉 电信
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Posted 2007-04-27 23:45 · 中国 广西 玉林 博白县 电信
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Output in the original format, cannot output blank lines
Can output blank lines, but each line must not contain the “line number:” characters that are the same as the line number, and it cannot output the “!、:” characters or the characters enclosed by “!、:” on the same line
[ Last edited by zh159 on 2007-4-27 at 10:49 AM ]
@echo off
for /l %%n in (3,1,90) do call :need %%n
pause
exit
:need
set /a line=%1-1
for /f "skip=%line% delims=" %%i in ('more test.txt') do (
echo %%i
goto :eof
)Can output blank lines, but each line must not contain the “line number:” characters that are the same as the line number, and it cannot output the “!、:” characters or the characters enclosed by “!、:” on the same line
@echo off
setlocal EnableDelayedExpansion
for /l %%n in (31,90) do call :need %%n
pause
exit
:need
set /a line=%1-1
for /f "skip=%line% delims=" %%i in ('findstr /n .* "test.txt"') do (
set "str=%%i"
set "str=!str:%1:=!"
if not "!str!" == "" (echo !str!) else echo.
goto :eof
)[ Last edited by zh159 on 2007-4-27 at 10:49 AM ]
Floor 10
Posted 2007-04-28 00:38 · 中国 甘肃 张掖 电信
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