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DOS批处理 & 脚本技术（批处理室） » Ask: How to count the number of lines of strings in a text

Floor1　bza2006	Posted 2007-03-22 08:23
初级用户　Posts 27　Credits 58
Count the number of strings in any line of the text. For example, if a line has "sdgdsg sdgdsg sdgfdgh", you can know there are 3 strings.

Floor2　lxmxn	Posted 2007-03-22 12:23
版主　Posts 4,938　Credits 11,386
Run the following batch script. Enter the file name to be checked, and after pressing Enter, the number of words per line will be displayed. Words are strings separated by spaces or horizontal tabs. @Echo Off&SetLocal EnableDelayedExpansion set/p file=Please input the file you want to check: if not defined file (echo Error&pause&exit/b) if not exist "%file%" (echo Error&pause&exit/b) for /f "delims=: tokens=1" %%a in ('findstr /n . "%file%"') do ( set b=&set a=%%b if not "!a!"=="" ( for %%h in (!a!) do set /a b+=1 echo/Line %%a:!b! words ) else (echo/Line %%a:0 words) ) pause

Floor3　bza2006	Posted 2007-03-22 20:42
初级用户　Posts 27　Credits 58
Thanks to the administrator for providing

Floor4　bza2006	Posted 2007-03-22 20:56
初级用户　Posts 27　Credits 58
Continuing to ask: What does!a! mean and how to use it?

Floor5　lxmxn	Posted 2007-03-22 21:22
版主　Posts 4,938　Credits 11,386
Re bza2006: !a! is equivalent to %a%, which means referencing the value of variable a. But it needs to use variable delay (setlocal enabledelayedexpansion) in for, so use! instead of % to reference its value. You can take a look at the following related explanations: http://www.cn-dos.net/forum/viewthread.php?tid=28273&fpage=1&highlight=%E5%8F%98%E9%87%8F%E5%BB%B6%E8%BF%9F http://www.cn-dos.net/forum/viewthread.php?tid=20733&fpage=1&highlight=%E5%8F%98%E9%87%8F%E5%BB%B6%E8%BF%9F

Floor6　bza2006	Posted 2007-03-23 08:14
初级用户　Posts 27　Credits 58
Thanks for the guidance, and I'm studying hard~