China DOS Union

Because the bat file needs to execute a certain file in the same directory, but the location of the bat file is uncertain. Originally written like this:
SET CurPath=%0
IF NOT "%CurPath%"=="" set CurPath=%CurPath:~0,-9%
echo %CurPath%
But sometimes it is correct when executed, and sometimes the result is wrong. Either there is one more character before and after, or one less character.
Who can help, thank you very much

%CD% This environment variable's content is the current directory.

Example: Display the current directory
@echo off echo The current directory is: %cd% pause

I know this. I mean, if I execute the bat like this:
C:\abc>D:\abc.bat
Then how to get "D:\abc"

The path obtained from '%~dp0' always has a \ as the last character, so you need to be careful when using it. For example, to call the abc.bat under it, you should write it as '%~dp0abc.bat'. Also, you don't know if there are spaces in the path, so it's best to enclose it in double quotes, or write it as '%~sdp0' in the short name form of the path.

That's amazing. Thanks a lot.

But, if your batch file (x.bat) is placed in a path with spaces, you will get nothing.

You can try:
[curpath.bat]
echo %cd% > curpath.txt

Just check curpath.txt.

```
>>curpath.txt echo="%cd%"
```

```
@echo off
setlocal EnableDelayedExpansion
echo Current path where the batch file is running: !cd!
pause
```

Originally posted by hxuan999 at 2007-1-19 12:50 AM:
The path obtained by '%~dp0' always ends with \, so you need to be careful when using it. For example, to call abc.bat under it, you should write it as '%~dp0abc.bat'.
In addition, you don't know if there are spaces in the path, so it's best to enclose it in double quotes, or write it as '%~sdp0' to use the short name form of the path.

Please teach me, what do '%~dp0' and '%~sdp0' specifically mean? Why didn't I see the path when I tried it?

To merryheart0424:

Demonstrate:
@echo off echo Current drive letter and path: %~dp0 echo Current drive letter and path in short filename format: %~sdp0 pause
Save it as a test.bat file and run it.

[ Last edited by lxmxn on 2007-5-25 at 03:10 PM ]

Originally posted by lxmxn at 2007-5-25 03:09 PM:
To merryheart0424:

Demonstrate:
@echo off echo Current drive letter and path: %~dp0 echo Current drive letter and path in short filename format: %~sdp0 pause
Save as test.bat and run...

The above works directly when run as a BAT file, but if compiled into an EXE file using a tool, the path will become the path of the system temporary directory :(

Also, if I only want to get the name of the parent directory of the current file, how to write it?
For example, the current file is C:\AAAA\BBB\TEST.BAT
I just want to get the directory name BBB

Thanks in advance

The above one can work when run directly in BAT mode, but it doesn't work when compiled into an EXE file with a tool. The path will become the path of the system temporary directory:(

The tool that compiles BAT files into EXE files is inflexible. A slight change to the batch script will cause problems. It seems that many extended functions of the batch script are not well completed by the compilation tool.

If you are just catering to the requirements of the compilation tool, that's another story.

For referring to getting the name of the parent directory of the current file, you can refer to the following code:
@echo off&SetLocal EnableDelayedExpansion set a=D:\abc\def ghi\j k\lmn.bat for %%a in ("%a%") do ( set ok=%%~dpa for /f "delims=" %%b in ("!ok:~0,-1!") do ( echo %%~nb ) ) pause

The parameter %0 is not invariable.
1. Double-click to execute in the resource manager
2. Run with full path in CMD
3. Run in the current directory in CMD