China DOS Union

A C programming problem. Please do it with batch processing. For example:

Input (seconds): 3662

Display: 0 days 1 hour 1 minute 2 seconds

The following is the simplified code:

```batch
@echo off
:begin
cls
set /a D=0,H=0,M=0,num=
set /p num= Please enter the number of seconds (press Enter directly to exit):
if not defined num exit
call :transform D %num% 86400
call :transform H %num% 3600
call :transform M %num% 60
echo %D% days %H% hours %M% minutes %num% seconds
pause
goto begin

:transform
set /a %1=%2/%3
if %1 gtr 0 set /a num=%2-%3*%1
goto :eof
```

```batch脚本代码，功能是获取用户输入的秒数，然后将其转换为天、小时、分钟和秒并输出。具体来说：
首先`@echo off`关闭命令回显，`:begin`是标签，`cls`清屏，然后获取用户输入的秒数，根据输入进行计算，分别得出天、小时、分钟、秒，最后输出并暂停后回到`:begin`标签继续循环。
代码内容如下：
```
@echo off
:begin
cls
echo.
set input=
set /p input= 请输入秒数(退出请直接按回车)：
if not defined input exit
set /a SS=%input%%%60
set /a MM=%input%/60%%60
set /a HH=%input%/3600%%60
set /a DD=%input%/86400%%60
echo.
echo %DD% 天 %HH% 小时 %MM% 分 %SS% 秒
echo.
pause
goto begin
```

Hehe, Brother zh159's thinking is more straightforward! I overcomplicated it.

Wonderful!!! Top~

A simple math problem ah
Hehe

The program should also be simple

If the input is xxxxx.34 and milliseconds need to be considered, then the code of the 2nd and 3rd floors cannot be executed

[ Last edited by scriptor on 2007-1-16 at 11:09 AM ]

When calculating the number of days on the 3rd floor, dividing by 60 to get the remainder will cause problems. The %%60 should be removed.

At that time, I wrote it casually , correction:

@echo off

:begin

cls

echo.

set input=

set /p input=  Please enter the number of seconds (press Enter directly to exit):

if not defined input exit

set /a SS=%input%%%60

set /a MM=%input%/60%%60

set /a HH=%input%/3600%%60

if %HH% GEQ 24 set /a HH=HH%%24

set /a DD=%input%/86400

echo.

echo   %DD% days %HH% hours %MM% minutes %SS% seconds

echo.

pause

goto begin

With milliseconds:
PS: Milliseconds are 1000 to 1 second

@echo off

:begin

cls

echo.

set input=

set /p input=  Please enter the number of seconds (press Enter directly to exit):

if not defined input exit

for /f "tokens=1* delims=." %%i in ("%input%") do set input=%%i&&set .n=%%j

if "%.n%" == "" set .n=0

if "%.n:~1%" == "" set .n=%.n%0

if "%.n:~2%" == "" set .n=%.n%0

if "%.n:~0,1%" == "0" set .n=%.n:~1%

if "%.n:~0,1%" == "0" set .n=%.n:~1%





set /a SS=%input%%%60

set /a MM=%input%/60%%60

set /a HH=%input%/3600%%60

if %HH% GEQ 24 set /a HH=HH%%24

set /a DD=%input%/86400

echo.

echo   %DD% days %HH% hours %MM% minutes %SS% seconds %.n% milliseconds

echo.

pause

goto begin

[ Last edited by zh159 on 2007-1-16 at 09:42 PM ]

There is a problem when dealing with milliseconds. For example, if you enter 5485.3, then.3 should be 300 milliseconds, not 3 milliseconds.

Originally posted by hxuan999 at 2007-1-16 13:37:
There is a problem when dealing with milliseconds. For example, entering 5485.3, then.3 should be 300 milliseconds, not 3 milliseconds.

Forgot -_-|||
Thanks for the reminder, it has been corrected, but it still cannot handle more than 4 decimal places

[ Last edited by zh159 on 2007-1-16 at 01:48 PM ]

I'll also do one with milliseconds (milliseconds with more than four decimal places are truncated to 000.00 milliseconds):

1. @echo off&setlocal enabledelayedexpansion
   
2. :begin
   
3. cls
   
4. echo;
   
5. set input=
   
6. set /p input= Please enter the number of seconds (press Enter directly to exit):
   
7. if not defined input exit
   
8. for /f "tokens=1* delims=." %%a in ("%input%") do set input=%%a & set D5=%%b00000
   
9. for /l %%i in (4,-1,2) do set /a "D%%i=!input!%%60" && set /a "input=!input!/60"
   
10. set "D5=!D5:~0,3!.!D5:~3,2!"
    
11. set /a "D1=!input!%%24"
    
12. echo;&echo; %D1% days %D2% hours %D3% minutes %D4% seconds %D5% milliseconds&echo;
    
13. pause
    
14. goto begin
    

hxuan： 2007-01-17 12:52

This program has been corrected.

[ Last edited by hxuan999 on 2007-1-17 at 01:59 PM ]

The code on floor 12 has the following defects:

1. Using the replacement statement to intercept the decimal part is error-prone. For example, when the integer part is a certain string of the decimal part, such as 23.1234. It is recommended not to use such an unconventional statement, and still use delims=. in the for statement to extract it;
2. When calculating the number of days, it is still divided by 60, which is incorrect.

```
@echo off
:start
setlocal
cls&echo.
set/p input=Please enter the number of seconds:
for /f "tokens=1,2 delims=." %%a in ("%input%") do set input=%%a&set input1=%%b
for /l %%a in (1,1,2) do set/a T%%a=input%%60,input/=60
set/a T3=input%%24,T4=input/24
set input1=%input1%0000
for /f "tokens=* delims=0" %%a in ("%input1:~0,4%") do set T0=%%a
echo/
if defined T0 (echo %T4% days %T3% hours %T2% minutes %T1% seconds %T0% milliseconds
) else (echo %T4% days %T3% hours %T2% minutes %T1% seconds)
echo\
pause
endlocal
goto start

```

You guys are amazing. You even got the milliseconds accurate. It seems it can be modified into a New Year's countdown to the Spring Festival^^