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DOS批处理 & 脚本技术（批处理室） » Batch processing to display consecutive letters?

Floor1　online365	Posted 2007-01-09 17:32
初级用户　Posts 75　Credits 182
For example, if I enter "af", it displays: a b c d e f Each letter occupies one line. I wonder if it can be achieved..

Floor2　qasa	Posted 2007-01-09 17:38
高级用户　Posts 311　Credits 959　From 广东-LianJiang
I think it should not work, unless characters can be converted into numbers to run, and then numbers are converted back to letters after running. This is the same principle as the post I previously posted about ASCII code and conversion between letters and numbers.

Floor4　namejm	Posted 2007-01-10 00:18
荣誉版主　Posts 1,737　Credits 5,226　From 成都
The following is the translated content: The demonstration code is as follows (no fault tolerance detection is done): @echo off set str=a b c d e f g h i j k l m n o p q r s t u v w x y z :begin cls set flag=0 set var= set input= set /p input= Please enter the letter range (such as af): for %%i in (%str%) do call :pickup %%i :end pause goto begin :pickup if /i "%1"=="%input:~0,1%" set flag=1 if /i "%1"=="%input:~-1%" set flag=2 if %flag% equ 1 echo %1 if %flag% equ 2 echo %1&goto end goto :eof

Floor5　youxi01	Posted 2007-01-10 02:09
高级用户　Posts 247　Credits 846　From 湖南==》广东
Let's play too^_^ @echo off setlocal enabledelayedexpansion set str=a b c d e f g h i j k l m n o p q r s t u v w x y z for %%i in (%str%) do set/a dec+=1 & set %%i=!dec! & set str!dec!=%%i set en= set /p en=Please enter the letter range (such as af): set/a num1=!%en:~0,1%!,num2=!%en:~-1%! for /l %%i in (%num1%,1,%num2%) do echo !str%%i! pause>nul

Floor6　youxi01	Posted 2007-01-10 02:21
高级用户　Posts 247　Credits 846　From 湖南==》广东
There is another one that is easier to understand: @echo off setlocal enabledelayedexpansion set str=a b c d e f g h i j k l m n o p q r s t u v w x y z set en= set /p en=Please enter the letter range (such as af): set str1=%en:~0,1% set str2=%en:~-1% for %%i in (%str%) do if %%i geq !str1! if %%i leq !str2! echo %%i pause>nul

Floor8　PPdos	Posted 2007-01-10 09:05
高级用户　Posts 268　Credits 783
@echo off :begin set /p a="Old rules, hee hee :" set str=a b c d e f g h i j k l m n o p q r s t u v w x y z for %%i in (%str%) do echo %%i\|findstr [%a:~0,1%-%a:~-1%] goto:begin

Floor9　namejm	Posted 2007-01-10 09:31
荣誉版主　Posts 1,737　Credits 5,226　From 成都
Then I'll come to another paragraph: @echo off :begin cls set str=a b c d e f g h i j k l m n o p q r s t u v w x y z set input= set /p input= Please enter the letter range (such as af): call set str=%%str:%input:~0,1%=-☆%input:~0,1%%% call set str=%%str:%input:~-1%=%input:~-1%☆%% for /f "tokens=2 delims=☆" %%i in ("%str%") do set str=%%i for %%i in (%str%) do echo %%i pause goto begin Simplify it further. [ Last edited by namejm on 2007-1-9 at 08:35 PM ]

Floor10　jmz573515	Posted 2007-01-10 22:38
银牌会员　Posts 464　Credits 1,212
Join in the fun m="a;b;c;d;e;f;g;h;i;j;k;l;m;n;o;p;q;r;s;t;u;v;w;x;y;z" s=split(m,";") b=inputbox("Please enter the letter range (e.g., af):","System Prompt") l=0 for i=0 to 25 if s(i)=left(b,1) then l=1 end if if l=1 then h=h&vbcrlf&s(i) end if if s(i)=right(b,1) then exit for next msgbox h

Floor11　youxi01	Posted 2007-01-11 02:26
高级用户　Posts 247　Credits 846　From 湖南==》广东
Originally posted by jmz573515 at 2007-1-10 10:38 PM: Join in the fun m="a;b;c;d;e;f;g;h;i;j;k;l;m;n;o;p;q;r;s;t;u;v;w;x;y;z" s=split(m,";") b=inputbox("Please enter the letter range (such as af):","System Prompt") l= ... If it's VBS, there's no need to be so complicated! Just use a simple for loop to get it done

Floor12　jmz573515	Posted 2007-01-11 02:57
银牌会员　Posts 464　Credits 1,212
I also hope the friend on the 11th floor can give some guidance. I'm just a beginner in VBS and don't know much about it. Thanks!

Floor13　huzixuan	Posted 2007-02-04 08:52
高级用户　Posts 219　Credits 537　From 芜湖
Today I finally understood the code on the 5th floor of the boss.

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