Let's Decrypt Batch Processing Encryption Passwords - China DOS Union Forum

### Reference Materials
Batch Code for Calculating String Length to Check for Errors

Hehe, see who can figure out the password. The last line is the password. You can delete this line and then execute it to create your own password.


@ECHO OFF
:TOP
SETLOCAL ENABLEDELAYEDEXPANSION
SET A_X=9
SET B_Y=9
SET C_Z=9
SET BOOT=1
SET BASE=%RANDOM%
CALL :CRY
IF NOT "%CRY%" == "" SET BOOT=0&&CALL :IN
SET DIC=abcdefghijklmnopqrstuvwxyz0123456789@ABCDEFGHIJKLMNOPQRSTUVWXYZ

CALL :LOS %DIC%
SET DL=%LOS%&&SET /A IDE=%LOS%%%9
IF %LOS% GTR 120 CLS&&ECHO Dictionary too long....&&GOTO END
IF NOT "%IDE%" == "0" ECHO Dictionary setting error&&GOTO END
:inp
IF "%BOOT%" == "1" (
SET MSG0=Start creating new password...&&SET MSG=Please enter new password&&SET MSG9=Creating password.
) ELSE SET MSG0=This document has password protection...&&SET MSG=Please enter&&SET MSG9=Verifying password.
ECHO.
ECHO   Password dictionary (password length cannot exceed 40 characters, dictionary length not exceed 120 characters):&&ECHO   %DIC%
ECHO   Case-sensitive, cannot set characters or spaces other than in the dictionary&&ECHO.
ECHO %MSG0%
:inp1
SET /P PWS="%MSG% PWS:>"
ECHO %PWS%|findstr /r "">nul&&GOTO INP
IF "%BOOT%" == "1" (
SET /P FWS="Enter again PWS:>"
IF NOT "%PWS%" == "!FWS!" (
SET MSG=The two entries are different. Please enter new password
GOTO INP1)
)
SET/P=%MSG9%<nul
CALL :LOS %PWS%
SET PL=%LOS%&&IF %LOS% GTR 40 ECHO Password length cannot exceed 40&&pause&&CLS&&GOTO TOP
SET NPL=%PL%

:calc
IF %NPL% GEQ %DL% SET /A NPL=%NPL%-%DL%&&GOTO CAL
SET /A HPL=%DL%-%NPL%
CALL :CONVERSE 0 %NPL% %NPL% %HPL%
CALL :CONVERSE -%NPL% %NPL% 0 -%NPL%

SET /A HDL=(%DL%-%DL%%%2)/2
SET ADL=!NDIC:~0,%HDL%!&&SET BDL=!NDIC:~%HDL%!&&SET NDIC=
FOR /L %%i IN (0,1,%HDL%) DO SET NDIC=!NDIC!!BDL:~%%i,1!!ADL:~%%i,1!

FOR /L %%z IN (0,1,%C_Z%) DO (
    FOR /L %%y IN (0,1,%B_Y%) DO (
        FOR /L %%x IN (0,1,%A_X%) DO (
        SET /a WD=1%%x%%y%%z%%%DL%
        CALL :TEXT !WD!
        SET _d_%%x%%y%%z=!TEXT!)
)
SET/P=.<nul)
::set _d_>1.txt&&goto chk


:create
FOR /L %%i IN (0,1,%NNPL%) DO (
FOR /F "tokens=2,3 delims=_=" %%a IN ('SET _d_^|find "=!PWS:~%%i,1!"') DO (
SET /A FF=!FF!+1
SET S!FF!=%%a
)
SET /A CF=%BASE%%%!FF!+1
CALL :OUT !CF!
SET/P=.<nul)
SET NCRY=%BASE%-%JG%
IF "%BOOT%" == "1" (
ECHO.>>"%~dpnx0"&&ECHO SET CRY=%NCRY%>>"%~dpnx0"
ECHO Password set successfully
GOTO END
) ELSE  IF "%NCRY%" == "%BASE%-%CRY%" (
ECHO Verification successful&&GOTO NEXT
) ELSE (
ECHO Password error&&pause&&GOTO ENDSET)

GOTO END
:los
SET STR=%1
FOR /L %%i IN (0,1,128) DO if "!STR:~%%i,1!" == "" SET LOS=%%i&&GOTO :EOF
GOTO :EOF

:text
SET TEXT=!NDIC:~%1,1!
GOTO :EOF

:converse
SET /A NNPL=%NPL%-1
SET _tmp2=
SET _tmp1=!DIC:~%1,%2!
FOR /L %%i IN (%NNPL%,-1,0) DO SET _tmp2=!_tmp2!!_tmp1:~%%i,1!
SET NDIC=%_tmp2%!DIC:~%3,%4!
GOTO :EOF

:out
SET JG=!JG!!S%1!&&SET FF=
GOTO :EOF

:in
FOR /F "tokens=1,2 delims=-" %%i IN ("%CRY%") DO SET BASE=%%i&&SET CRY=%%j
CALL :LOS %CRY%
SET HCRY=%LOS%&&SET /A CHK=%LOS%%%3
IF NOT "%CHK%" == "0" ECHO Ciphertext damaged！&&GOTO END
GOTO :EOF

:endset
ENDLOCAL&cls
GOTO TOP

:next
ECHO OK..
GOTO END

:chk
::check label:calc matrix
for /l %%j in (0,1,62) do (
set /a sh=0
for /f "tokens=2 delims==" %%i in (1.txt) do (
if "!DIC:~%%j,1!" == "%%i" set /a sh=!sh!+1)
echo !DIC:~%%j,1! !sh! >>sh.txt)

:end
rem copyright:12232-530502-12000-046006035061035000002030034
PAUSE>nul
EXIT

:cry
::SET /A NDL=%DL%-1
::FOR /L %%i IN (0,1,%NDL%) DO ECHO %PWS%|find "!NDIC:~%%i,1!">nul&&SET BIY=!BIY!!NDIC:~%%i,1!
SET CRY=7304-552511527557551535939937543939547

[ Last edited by everest79 on 2006-12-31 at 05:06 AM ]

%RANDOM%
How is it possible to be reversed calculated???

Is it reverse enumeration????

Originally posted by tghksj at 2006-12-31 03:28 PM:
%RANDOM%
How is it possible to be reversed?

Is it reverse enumeration?????

When the password exists, the assigned %random% is replaced. Take a closer look at the IN section

Originally posted by Michale at 2006-12-31 04:04 PM:
Let's try~~

Come on, this password can indeed be calculated by a very simple method
Because of the calculation time issue, I deleted one part of the encryption, otherwise it would take a lot of time

The password is


DOSlianmeng

The biggest loophole in this encryption is that the password length is the key to calculation. As long as you enumerate password lengths from 1 to 40, you can obtain the encryption matrix, then reverse look up the ciphertext, and divide it into segments of three characters each to get the password.

The theoretical value is very high, but the practical value is not high.

Batch processing code is very easy to be modified, so it is not suitable for use as a password verification program.

It can indeed be used for text encryption, but the efficiency is worrying.

Moreover, the fact that this algorithm does not require a key for decryption also reduces security.

[ Last edited by qzwqzw on 2007-1-1 at 12:56 PM ]

Originally posted by qzwqzw at 2007-1-1 12:47 PM:
Theoretical value is very high, but practical value is not high

Batch processing code is easy to be modified, so it is not suitable for use as a password verification program

It can be used for text encryption, but the efficiency is worrying

And this calculation ...

These days I've been thinking about how this encryption can perform deep calculations without taking a long time. I post it just hoping everyone can have their own opinions. The envisioned application object is to encrypt the batch processing itself. Actually, it can't be regarded as real encryption because it's impossible to achieve the one-into-three integration of encryption standards. It's just setting an additional hurdle, increasing a bit of difficulty while adding more fun at the same time

Decryption P processing. Directly copied from the building block code of the original poster.

@echo off
SETLOCAL ENABLEDELAYEDEXPANSION
SET A_X=9
SET B_Y=9
SET C_Z=9
SET DIC=abcdefghijklmnopqrstuvwxyz0123456789@ABCDEFGHIJKLMNOPQRSTUVWXYZ
set error=    Incorrect ciphertext format.
CALL :LOS %DIC%
SET DL=%LOS%
cls
:TOP

set NCRY=
set/p NCRY=Please enter ciphertext:
if not defined NCRY goto :top
for /f "tokens=1,2 delims=-" %%i in ("%NCRY%") do set BASE=%%i&set JG=%%j
if not defined BASE echo %error% & goto :top
if not defined JG echo %error% & goto :top
call :los %JG%
set/a NPL=%LOS%/3
set/a MPL=%LOS%%%3
if not %MPL%==0 echo %error% & goto :top

SET /A HPL=%DL%-%NPL%
CALL :CONVERSE -%NPL% %NPL% 0 -%NPL%

SET /A HDL=(%DL%-%DL%%%2)/2
SET ADL=!NDIC:~0,%HDL%!&&SET BDL=!NDIC:~%HDL%!&&SET NDIC=
FOR /L %%i IN (0,1,%HDL%) DO SET NDIC=!NDIC!!BDL:~%%i,1!!ADL:~%%i,1!

FOR /L %%z IN (0,1,%C_Z%) DO (
    FOR /L %%y IN (0,1,%B_Y%) DO (
        FOR /L %%x IN (0,1,%A_X%) DO (
        SET /a WD=1%%x%%y%%z%%%DL%
        CALL :TEXT !WD!
        SET _d_%%x%%y%%z=!TEXT!)
)
SET/P=.<nul)

set /a enpl=nnpl*3

echo.Password is:
for /l %%i in (0,3,!enpl!) do (
	for /f "tokens=2 delims==" %%j in ('set _d_^|find "!JG:~%%i,3!"') do (
		set/p=%%j<nul
	)
)
echo. & pause>nul
EXIT/B


:converse
SET /A NNPL=%NPL%-1
SET _tmp2=
SET _tmp1=!DIC:~%1,%2!
FOR /L %%i IN (%NNPL%,-1,0) DO SET _tmp2=!_tmp2!!_tmp1:~%%i,1!
SET NDIC=%_tmp2%!DIC:~%3,%4!
GOTO :EOF

:text
SET TEXT=!NDIC:~%1,1!
GOTO :EOF

:los
SET STR=%1
FOR /L %%i IN (0,1,128) DO if "!STR:~%%i,1!" == "" SET LOS=%%i&&GOTO :EOF
GOTO :EOF

[ Last edited by 0401 on 2007-1-3 at 08:27 AM ]

Originally posted by everest79 at 2007-1-1 23:16:

Come on, this password can indeed be calculated through a very simple method
Because of the calculation time issue, I deleted one part of the encryption, otherwise it would take a lot of time

Can the owner of the post post the complete version?

Floor1　everest79	Posted 2006-12-31 18:05
金牌会员　Posts 1,127　Credits 2,564
### Reference Materials Batch Code for Calculating String Length to Check for Errors Hehe, see who can figure out the password. The last line is the password. You can delete this line and then execute it to create your own password. @ECHO OFF :TOP SETLOCAL ENABLEDELAYEDEXPANSION SET A_X=9 SET B_Y=9 SET C_Z=9 SET BOOT=1 SET BASE=%RANDOM% CALL :CRY IF NOT "%CRY%" == "" SET BOOT=0&&CALL :IN SET DIC=abcdefghijklmnopqrstuvwxyz0123456789@ABCDEFGHIJKLMNOPQRSTUVWXYZ CALL :LOS %DIC% SET DL=%LOS%&&SET /A IDE=%LOS%%%9 IF %LOS% GTR 120 CLS&&ECHO Dictionary too long....&&GOTO END IF NOT "%IDE%" == "0" ECHO Dictionary setting error&&GOTO END :inp IF "%BOOT%" == "1" ( SET MSG0=Start creating new password...&&SET MSG=Please enter new password&&SET MSG9=Creating password. ) ELSE SET MSG0=This document has password protection...&&SET MSG=Please enter&&SET MSG9=Verifying password. ECHO. ECHO Password dictionary (password length cannot exceed 40 characters, dictionary length not exceed 120 characters):&&ECHO %DIC% ECHO Case-sensitive, cannot set characters or spaces other than in the dictionary&&ECHO. ECHO %MSG0% :inp1 SET /P PWS="%MSG% PWS:>" ECHO %PWS%\|findstr /r "">nul&&GOTO INP IF "%BOOT%" == "1" ( SET /P FWS="Enter again PWS:>" IF NOT "%PWS%" == "!FWS!" ( SET MSG=The two entries are different. Please enter new password GOTO INP1) ) SET/P=%MSG9%<nul CALL :LOS %PWS% SET PL=%LOS%&&IF %LOS% GTR 40 ECHO Password length cannot exceed 40&&pause&&CLS&&GOTO TOP SET NPL=%PL% :calc IF %NPL% GEQ %DL% SET /A NPL=%NPL%-%DL%&&GOTO CAL SET /A HPL=%DL%-%NPL% CALL :CONVERSE 0 %NPL% %NPL% %HPL% CALL :CONVERSE -%NPL% %NPL% 0 -%NPL% SET /A HDL=(%DL%-%DL%%%2)/2 SET ADL=!NDIC:~0,%HDL%!&&SET BDL=!NDIC:~%HDL%!&&SET NDIC= FOR /L %%i IN (0,1,%HDL%) DO SET NDIC=!NDIC!!BDL:~%%i,1!!ADL:~%%i,1! FOR /L %%z IN (0,1,%C_Z%) DO ( FOR /L %%y IN (0,1,%B_Y%) DO ( FOR /L %%x IN (0,1,%A_X%) DO ( SET /a WD=1%%x%%y%%z%%%DL% CALL :TEXT !WD! SET _d_%%x%%y%%z=!TEXT!) ) SET/P=.<nul) ::set _d_>1.txt&&goto chk :create FOR /L %%i IN (0,1,%NNPL%) DO ( FOR /F "tokens=2,3 delims=_=" %%a IN ('SET _d_^\|find "=!PWS:~%%i,1!"') DO ( SET /A FF=!FF!+1 SET S!FF!=%%a ) SET /A CF=%BASE%%%!FF!+1 CALL :OUT !CF! SET/P=.<nul) SET NCRY=%BASE%-%JG% IF "%BOOT%" == "1" ( ECHO.>>"%~dpnx0"&&ECHO SET CRY=%NCRY%>>"%~dpnx0" ECHO Password set successfully GOTO END ) ELSE IF "%NCRY%" == "%BASE%-%CRY%" ( ECHO Verification successful&&GOTO NEXT ) ELSE ( ECHO Password error&&pause&&GOTO ENDSET) GOTO END :los SET STR=%1 FOR /L %%i IN (0,1,128) DO if "!STR:~%%i,1!" == "" SET LOS=%%i&&GOTO :EOF GOTO :EOF :text SET TEXT=!NDIC:~%1,1! GOTO :EOF :converse SET /A NNPL=%NPL%-1 SET _tmp2= SET _tmp1=!DIC:~%1,%2! FOR /L %%i IN (%NNPL%,-1,0) DO SET _tmp2=!_tmp2!!_tmp1:~%%i,1! SET NDIC=%_tmp2%!DIC:~%3,%4! GOTO :EOF :out SET JG=!JG!!S%1!&&SET FF= GOTO :EOF :in FOR /F "tokens=1,2 delims=-" %%i IN ("%CRY%") DO SET BASE=%%i&&SET CRY=%%j CALL :LOS %CRY% SET HCRY=%LOS%&&SET /A CHK=%LOS%%%3 IF NOT "%CHK%" == "0" ECHO Ciphertext damaged！&&GOTO END GOTO :EOF :endset ENDLOCAL&cls GOTO TOP :next ECHO OK.. GOTO END :chk ::check label:calc matrix for /l %%j in (0,1,62) do ( set /a sh=0 for /f "tokens=2 delims==" %%i in (1.txt) do ( if "!DIC:~%%j,1!" == "%%i" set /a sh=!sh!+1) echo !DIC:~%%j,1! !sh! >>sh.txt) :end rem copyright:12232-530502-12000-046006035061035000002030034 PAUSE>nul EXIT :cry ::SET /A NDL=%DL%-1 ::FOR /L %%i IN (0,1,%NDL%) DO ECHO %PWS%\|find "!NDIC:~%%i,1!">nul&&SET BIY=!BIY!!NDIC:~%%i,1! SET CRY=7304-552511527557551535939937543939547 [ Last edited by everest79 on 2006-12-31 at 05:06 AM ]

Floor3　tghksj	Posted 2007-01-01 04:28
社区乞丐　Posts 90　Credits -49
%RANDOM% How is it possible to be reversed calculated??? Is it reverse enumeration????

Floor5　everest79	Posted 2007-01-01 23:13
金牌会员　Posts 1,127　Credits 2,564
Originally posted by tghksj at 2006-12-31 03:28 PM: %RANDOM% How is it possible to be reversed? Is it reverse enumeration????? When the password exists, the assigned %random% is replaced. Take a closer look at the IN section

Floor6　everest79	Posted 2007-01-01 23:16
金牌会员　Posts 1,127　Credits 2,564
Originally posted by Michale at 2006-12-31 04:04 PM: Let's try~~ Come on, this password can indeed be calculated by a very simple method Because of the calculation time issue, I deleted one part of the encryption, otherwise it would take a lot of time

Floor7　everest79	Posted 2007-01-02 01:03
金牌会员　Posts 1,127　Credits 2,564
The password is DOSlianmeng The biggest loophole in this encryption is that the password length is the key to calculation. As long as you enumerate password lengths from 1 to 40, you can obtain the encryption matrix, then reverse look up the ciphertext, and divide it into segments of three characters each to get the password.

Floor2　everest79	Posted 2006-12-31 23:56
金牌会员　Posts 1,127　Credits 2,564

Floor4　Michale	Posted 2007-01-01 05:04
初级用户　Posts 27　Credits 52　From ☆逍遥宫☆

Floor8　qzwqzw	Posted 2007-01-02 01:47
银牌会员　Posts 636　Credits 2,343
The theoretical value is very high, but the practical value is not high. Batch processing code is very easy to be modified, so it is not suitable for use as a password verification program. It can indeed be used for text encryption, but the efficiency is worrying. Moreover, the fact that this algorithm does not require a key for decryption also reduces security. [ Last edited by qzwqzw on 2007-1-1 at 12:56 PM ]

Floor9　everest79	Posted 2007-01-02 06:46
金牌会员　Posts 1,127　Credits 2,564
Originally posted by qzwqzw at 2007-1-1 12:47 PM: Theoretical value is very high, but practical value is not high Batch processing code is easy to be modified, so it is not suitable for use as a password verification program It can be used for text encryption, but the efficiency is worrying And this calculation ... These days I've been thinking about how this encryption can perform deep calculations without taking a long time. I post it just hoping everyone can have their own opinions. The envisioned application object is to encrypt the batch processing itself. Actually, it can't be regarded as real encryption because it's impossible to achieve the one-into-three integration of encryption standards. It's just setting an additional hurdle, increasing a bit of difficulty while adding more fun at the same time

Floor10　0401	Posted 2007-01-03 08:24
中级用户　Posts 88　Credits 435
Decryption P processing. Directly copied from the building block code of the original poster. @echo off SETLOCAL ENABLEDELAYEDEXPANSION SET A_X=9 SET B_Y=9 SET C_Z=9 SET DIC=abcdefghijklmnopqrstuvwxyz0123456789@ABCDEFGHIJKLMNOPQRSTUVWXYZ set error= Incorrect ciphertext format. CALL :LOS %DIC% SET DL=%LOS% cls :TOP set NCRY= set/p NCRY=Please enter ciphertext: if not defined NCRY goto :top for /f "tokens=1,2 delims=-" %%i in ("%NCRY%") do set BASE=%%i&set JG=%%j if not defined BASE echo %error% & goto :top if not defined JG echo %error% & goto :top call :los %JG% set/a NPL=%LOS%/3 set/a MPL=%LOS%%%3 if not %MPL%==0 echo %error% & goto :top SET /A HPL=%DL%-%NPL% CALL :CONVERSE -%NPL% %NPL% 0 -%NPL% SET /A HDL=(%DL%-%DL%%%2)/2 SET ADL=!NDIC:~0,%HDL%!&&SET BDL=!NDIC:~%HDL%!&&SET NDIC= FOR /L %%i IN (0,1,%HDL%) DO SET NDIC=!NDIC!!BDL:~%%i,1!!ADL:~%%i,1! FOR /L %%z IN (0,1,%C_Z%) DO ( FOR /L %%y IN (0,1,%B_Y%) DO ( FOR /L %%x IN (0,1,%A_X%) DO ( SET /a WD=1%%x%%y%%z%%%DL% CALL :TEXT !WD! SET _d_%%x%%y%%z=!TEXT!) ) SET/P=.<nul) set /a enpl=nnpl3 echo.Password is: for /l %%i in (0,3,!enpl!) do ( for /f "tokens=2 delims==" %%j in ('set _d_^\|find "!JG:~%%i,3!"') do ( set/p=%%j<nul ) ) echo. & pause>nul EXIT/B :converse SET /A NNPL=%NPL%-1 SET _tmp2= SET _tmp1=!DIC:~%1,%2! FOR /L %%i IN (%NNPL%,-1,0) DO SET _tmp2=!_tmp2!!_tmp1:~%%i,1! SET NDIC=%_tmp2%!DIC:~%3,%4! GOTO :EOF :text SET TEXT=!NDIC:~%1,1! GOTO :EOF :los SET STR=%1 FOR /L %%i IN (0,1,128) DO if "!STR:~%%i,1!" == "" SET LOS=%%i&&GOTO :EOF GOTO :EOF [ Last edited by 0401 on 2007-1-3 at 08:27 AM* ]

Floor11　0401	Posted 2007-01-03 08:32
中级用户　Posts 88　Credits 435
Originally posted by everest79 at 2007-1-1 23:16: Come on, this password can indeed be calculated through a very simple method Because of the calculation time issue, I deleted one part of the encryption, otherwise it would take a lot of time Can the owner of the post post the complete version?