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DOS批处理 & 脚本技术（批处理室） » How to get the characters before the double quotation mark

Floor1　roby	Posted 2006-12-22 11:50
新手上路　Posts 4　Credits 12
I have a text The content is as follows var URL = "adsdt.phpuser=sdfsd1&time=1166712303"; The numbers in it are changing I now want to take out this number for /f "tokens=4 delims==" %%i in (z1.txt) do echo %%i > z2.txt This can only take out 1166712303"; I don't know how to only take out the number Ask all the experts Thank you [ Last edited by namejm on 2006-12-21 at 10:58 PM ]

Floor2　namejm	Posted 2006-12-22 11:58
荣誉版主　Posts 1,737　Credits 5,226　From 成都
``` @echo off for /f "tokens=4 delims==" %%i in (test.txt) do set str=%%i echo %str:~0,-2% pause ```

Floor3　roby	Posted 2006-12-22 11:59
新手上路　Posts 4　Credits 12
Thanks thanks I know very little about batch processing I need to study and learn the code from the friend above :) Friend, can you explain echo %str:~0,-2% Or please give me relevant tutorials to learn, thanks [ Last edited by roby on 2006-12-21 at 11:01 PM ]

Floor4　namejm	Posted 2006-12-22 12:16
荣誉版主　Posts 1,737　Credits 5,226　From 成都
Please refer to post 10F of this thread: http://www.cn-dos.net/forum/viewthread.php?tid=24485&sid=ful3YN