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DOS批处理 & 脚本技术（批处理室） » How to implement variable substitution for variables?

Floor1　pigvip	Posted 2006-10-11 06:58
新手上路　Posts 6　Credits 17
set a=123 set b=1234 How to replace the same parts in b with 0 using variable a? Is it like this? How to write variable A? echo %b:a=0%

Floor2　pengfei	Posted 2006-10-11 08:46
银牌会员　Posts 485　Credits 1,218　From 湖南.娄底
The code is as follows: @echo off setlocal enabledelayedexpansion set a=123 set b=1234 set "b=!b:%a%=0!" echo %b% pause

Floor3　weilong888	Posted 2006-10-11 09:33
银牌会员　Posts 548　Credits 1,270
If set a=123 set b=1234 And finally, how to write the code so that echo %b% displays 0004?

Floor4　namejm	Posted 2006-10-11 09:38
荣誉版主　Posts 1,737　Credits 5,226　From 成都
Originally posted by weilong888 at 2006-10-11 09:33: If set a=123 set b=1234 And finally, how to make echo %b% display 0004? How should this code be written? Change set "b=!b:%a%=0!" to set "b=!b:%a%=000!" to achieve it.

Floor5　3742668	Posted 2006-10-12 07:01
荣誉版主　Posts 718　Credits 2,013
It is also possible to use environment variables without enabling delay, but there are relatively large limitations: set "a=123" set "b=1234" echo %b:%a%=000% \| findstr .