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The time now is 2026-08-01 23:13 		48,037 topics / 350,122 posts / today 2 new / 48,250 members
DOS开发编程 & 发展交流 （开发室） » It looks like an illegal statement, but it can actually be compiled and run successfully, and the result is correct!
Printable Version 　1,568 / 3
Floor1　GOTOmsdos Posted 2006-07-28 21:39
铂金会员　Posts 1,827　Credits 5,154
In the source code of GZIP in GNU, when compiled on TC2, it passes.

#define FLUSH_BLOCK(eof) \
flush_block(block_start >= 0L ? (char*)&window[(unsigned)block_start] : \
(char*)NULL, (long)strstart - block_start, (eof))

With the above macro definition, there is the following statement that feels violating regulations later!
if (flush) FLUSH_BLOCK(0), block_start = strstart;

Attention!!! The above "comma" (not semicolon)!!!
Floor2　asbai Posted 2006-07-29 04:01
高级用户　Posts 252　Credits 653
What's wrong with commas? In C/C++ grammar, expressions separated by commas are evaluated from left to right, and the value of the entire expression is the value of the rightmost sub-expression.

Are function calls and assignments both legal expressions?

Floor3　electronixtar Posted 2006-07-29 14:47
铂金会员　Posts 2,672　Credits 7,493
Floor4　GOTOmsdos Posted 2006-07-29 22:51
铂金会员　Posts 1,827　Credits 5,154
Yes, comma expression
Reviewed
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