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DOS批处理 & 脚本技术（批处理室） » How to count the number of times a certain string appears in a text?

Floor1　namejm	Posted 2006-06-14 19:39
荣誉版主　Posts 1,737　Credits 5,226　From 成都
For example, there is a text file with several lines of content, such as: 1,2,3,4 7,8,9,10 …… How to count the number of commas in it?

Floor2　bagpipe	Posted 2006-06-15 10:53
银牌会员　Posts 425　Credits 1,144　From 北京
In fact, I don't have a very good way for this kind of question. I think the limitations are also very big, and I haven't found a good way to solve it. But the landlord can try the following code: @echo off setlocal enabledelayedexpansion set a= for /f "delims=" %%a in (要检索的文件.txt) do set a=!a!%%a :back set /a b+=1 set a=%a:*,=% if "%a%"=="这里是最后一个逗号后面内容" goto end goto back :end echo There are %b% commas

Floor3　piziliu2004	Posted 2006-06-15 13:50
中级用户　Posts 139　Credits 321
to: bAGPIPE What does set a=%a:*,=% mean?

Floor4　kcdsw	Posted 2006-06-15 15:23
中级用户　Posts 179　Credits 404
Look at help set 变量名=%变量:1=2% This means to replace 1 in front with 2 after =.

Floor5　namejm	Posted 2006-06-15 16:07
荣誉版主　Posts 1,737　Credits 5,226　From 成都
Thanks to bagpipe, I can use it with a little modification based on your code. ——The limitation you mentioned should be that the content after the last comma in "if "%a%"=="here is the content after the last comma" goto end" needs to be entered manually, right?

Floor6　bagpipe	Posted 2006-06-16 08:30
银牌会员　Posts 425　Credits 1,144　From 北京
The limitations I mentioned are not what Brother namejm said. In fact, I can get the content after the last comma. The limitation I mentioned is because you assign all the characters in the file to a variable, and then how many characters this variable can bear at most. If there is no content after the last comma, this situation will not be the case.