China DOS Union

Under the condition of having only one CD-ROM drive, FINDCD can be used to determine the drive letter of the CD-ROM drive. How to determine the drive letter of the last partition of the hard disk (excluding NTFS partitions) according to this drive letter? When creating a directory name, and how to determine whether the directory name exists? Please experts answer.

I also want to know the answer

I want to know too

http://www.cn-dos.net/forum/viewthread.php?tid=14465&fpage=1
Here is the answer you need.

『Post #5』:

OK, just now I added an option /L to FINDCD to display and set the drive letter before the first CD-ROM to %CDROM%. Let's give it a try:
Open the attachment
For example, suppose the CD-ROM is D:
FINDCD /L
CDROM=C:

Attachment cannot be downloaded

Use the following method

func -a6>list.txt // Write all partition drive letters to list.txt (excluding CD-ROM drives)
STRINGS a=LINESIZE list.txt // Return the total number of lines in the file content
STRINGS p=READ list.txt,%a% // Read the content of the specified line in the file
echo %p% // %p% is the drive letter of the last partition

There is another method, you can try.
Use MD
if exist to judge the drive letter of the last partition.
You can try the following method.
@echo off set drv=c d e f g h i j k l m n o p q r s t u v w x y z if "%1"=="" if "%last_drv%"=="" call %0 %drv% :set_last if "%1"=="" goto end md %1:\last.drv>nul if not exist %1:\last.drv\nul goto end rd %1:\last.drv>nul set last_drv=%1: shift goto set_last :end

It all looks quite impressive. Let's do one too:

@echo off
cd\
set c=C:
set d=D:
set e=E:
set f=F:
set g=G:
set h=H:
set i=I:
set j=J:
set k=K:
set l=L:
set m=M:
set n=N:
set o=O:
set p=P:
set q=Q:
set r=R:
set s=S:
set t=T:
set u=U:
set v=V:
set w=W:
set x=X:
set y=Y:
set z=Z:

%c%
%d%
%E%
%f%
%g%
%h%
%i%
%j%
%k%
%l%
%m%
%n%
%o%
%p%
%q%
%r%
%s%
%t%
%u%
%v%
%w%
%x%
%y%
%z%

if "%cd%" == "%d%\" %c%
if "%cd%" == "%e%\" %d%
if "%cd%" == "%f%\" %e%
if "%cd%" == "%g%\" %f%
if "%cd%" == "%h%\" %g%
if "%cd%" == "%i%\" %h%
if "%cd%" == "%j%\" %i%
if "%cd%" == "%k%\" %j%
if "%cd%" == "%l%\" %k%
if "%cd%" == "%m%\" %l%
if "%cd%" == "%n%\" %m%
if "%cd%" == "%o%\" %n%
if "%cd%" == "%p%\" %o%
if "%cd%" == "%q%\" %p%
if "%cd%" == "%r%\" %q%
if "%cd%" == "%s%\" %r%
if "%cd%" == "%t%\" %s%
if "%cd%" == "%u%\" %t%
if "%cd%" == "%v%\" %u%
if "%cd%" == "%w%\" %v%
if "%cd%" == "%x%\" %w%
if "%cd%" == "%y%\" %x%
if "%cd%" == "%z%\" %y%

Tested in the command line and it works. Assume there's a disk in the CD-ROM and it can be accessed in the command line. The reason for writing it so long is to make it easy to execute under DOS. Not sure if there's the %cd% environment variable under DOS. Bored friends, help test it under DOS and pay attention to the case of the statements.

[ Last edited by 3742668 on 2006-3-12 at 22:49 ]

If the system is set with a memory virtual disk during startup, then all the above programs will become invalid.

Haha, the two upstairs are really funny.
I will only think you are awesome if you can provide a perfect solution.
Otherwise, just go stay aside.

Originally posted by Climbing at 2006-3-13 00:31:
If the system sets up a memory virtual disk during startup, then all the above programs will become invalid.

It's okay if the virtual memory disk is set up, because the total number of lines returned by strings is always one less than the actual number of lines, and the total number of lines obtained by "strings read file" returns the content of the second-to-last line, which is exactly the answer this question wants. As for why the last line is not read with the total number of lines it returns, I haven't figured it out yet, heh heh.

Output format of func -a6:

C
D
E
.
.
.
X :: X is the virtual memory disk letter