Also, I want to ask what the R.BAT file in your DOS boot disk is for? If you really want to boot the Win9x interface from the MS-DOS 7.10 boot disk, you just need to set winbootdir=. in MSDOS.SYS. In this way, no matter where Win9x is installed (whether it's C:\WINDOWS or D:\WIN98, etc.), after booting with the DOS boot disk, as long as you enter the Win9x folder and type the WIN command, you can enter the Win9x interface (and this setting will not affect the boot of the DOS boot disk at all. My latest MS-DOS 7.10 boot disk is set this way). For example:
A:\>D:
D:\>CD \WIN98
D:\WIN98>WIN
You can start the Win98 GUI in the D:\WIN98 folder.
Note: The permanent download address of my latest MS-DOS 7.10 boot disk (currently the 2003-3-27 version) is:
http://newdos.yginfo.net/dosware/mdos71bd.zip
Also, the "ATTRIB -S -H -R -A xxx" in the R.BAT file is actually not necessary to be so complicated. You can directly use "ATTRIB , xxx" or "ATTRIB -SHRA xxx".
Wengier - 新DOS时代
欢迎大家来到我的“新DOS时代”网站,里面有各类DOS软件和资料,地址:
http://wendos.mycool.net/
E-Mail & MSN: wengierwu AT hotmail.com (最近比较忙,有事请联系DOSroot和雨露,谢谢!)
