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中国DOS联盟论坛 The time now is 2026-10-27 16:45 |
47,815 topics / 349,928 posts / today 0 new / 48,289 members |
| DOS启动盘 & LOGO技术 （启动盘室） » Question about BAT files |
| Printable Version 837 / 4 |
| Floor1 beidouking | Posted 2004-08-04 00:00 |
| 初级用户 Posts 7 Credits 126 | |
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:loop
if errorlevel %1 goto no_shift :do_shift set cdrom=%2 shift shift if not %1*==* goto loop goto no_ramdrive Can someone give a detailed explanation? This is from SETRAMD.BAT on the 98 boot disk. Thanks in advance |
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| Floor2 JonePeng | Posted 2004-08-04 00:00 |
| 金牌会员 Posts 1,883 Credits 4,562 From 广东广州 | |
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These few lines are for finding the drive letter of the virtual hard disk; only by looking together with autoexec.bat can you know their whole background. Indeed, these few lines are written so～～～terse!!! Just a few batch statements, and by using shift and a loop they actually outperform an assembly program! Impressive! I need to study this seriously too。。。。。。
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| Floor3 wchong | Posted 2004-08-04 00:00 |
| 银牌会员 Posts 510 Credits 1,186 | |
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Wow! So BAT can be this powerful too!
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| Floor4 je64 | Posted 2004-08-07 00:00 |
| 初级用户 Posts 16 Credits 168 | |
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What is shift used for here?
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| Floor5 JonePeng | Posted 2004-08-08 00:00 |
| 金牌会员 Posts 1,883 Credits 4,562 From 广东广州 | |
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Shift moves all command-line parameters one place to the left. For example, if there are five parameters, %1 %2 %3 %4 %5, after one shift they become %2 %3 %4 %5, and after another shift they become %3 %4 %5, and so on.
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