China DOS Union

I don't know if this meets the requirements:

@echo off

set c1=5

set c2=3

set/a pen=2*c2/(c1-c2)

set/a 温差=(pen+1)*c1

set/a 温升=(温差-c1-c2)/(pen+3)

echo There were originally %pen% cups of water, and the temperature difference between the water in the basin and the water in the cup was %温差% degrees.

echo Now the temperature rise is %温升% degrees.

pause

Completely correct

I don't know what other questions are there?

The problem has been updated

First, the simplest 25, 26

25. "Chick and Rabbit in the Same Cage"

@echo off

setlocal enabledelayedexpansion



for /l %%i in (1 1 79) do (

    set /a chick_num=%%i

    set /a dog_num=79-!chick_num!

    set /a footnum=2*!chick_num!+4*!dog_num!

    if !footnum! EQU 200 (

        set msg1=The number of chicks is:!chick_num!

        set msg2=The number of dogs is:!dog_num!

        goto :exit

     )

)

:exit

    echo %msg1%

    echo %msg2%

pause>nul

26. The problem of big and small monks;

@echo off

setlocal enabledelayedexpansion



for /l %%i in (0 4 100) do (

    set /a small=%%i/4

    set /a big=400-%%i*4

    set /a total=!small!+!big!

    if !total! EQU 100 (

        set msg1=The number of small monks is:%%i

        set /a num=100-%%i

        set msg2=The number of big monks is:!num!

        goto :exit

    )

)



:exit

   echo %msg1%

   echo %msg2%



pause>nul

Question 23, the problem of weighing beads, should discard the "lucky" situation, if I am lucky, maybe I can do it in two times! ^--^

@echo off

setlocal enabledelayedexpansion

set flag=1

call :test 243

echo At least should be: %flag% times



pause>nul



:test

   set /a tmp=%1 %% 2

   set /a num=%1

   if %tmp% NEQ 0 set /a num-=1

       if %num% geq 2 (

          set /a num/=2

          set /a flag+=1

          call :test !num!)

   goto :eof

I'll also post two questions:

1. Find prime numbers (with relatively high efficiency requirements)
2. Find the numbers within 1-49 such that the product of any two numbers is equal, for example: 2*3=6 and 1*6=6

Looking forward~ ~ Must not let a good post sink~ :)

Find prime numbers within 10000

@echo off

setlocal enabledelayedexpansion

echo Prime numbers within 10000 are:

set/p a= 2 3 5 7 <nul

for /l %%a in (9 2 99) do (set/a a=%%a%%3

set/a b=%%a%%5

set/a c=%%a%%7

if not !a!==0 if not !b!==0 if not !c!==0 set/p a=%%a <nul)

for /l %%a in (101 2 9999) do (for /l %%b in (3 2 97) do (set/a a=%%a%%%%b

if !a!==0 set b=1) 

if not !b!==1 set/p a=%%a <nul

set b=0)

Question 24:
```
@echo off
:1
set/a a+=3
set/a b+=1
if not %a%==9 goto 1
echo This frog needs to jump %b% times to get out of the well
pause
```
Question 25:
```
@echo off
set/a a=(200-79*2)/(4-2)
set/a b=79-a
echo There are %b% chickens and %a% dogs
pause
```

Question 26:

@echo off

set/a a=(100*4-100*1)/(4*4-1)

set/a b=100-a

echo There are %b% little monks, and %a% big monks

pause

Appreciate the prime number search program by the moderator;

It seems that the moderator's solution for 24, 25, 26 is by solving equations oh

Find numbers within 1-43 such that the product of any two numbers is equal (e.g., 2*3=6 and 1*6=6)

Paste a piece of my immature code:

@echo off

setlocal enabledelayedexpansion



for /l %%a in (2 1 49) do (

   for /l %%b in (%%a 1 49) do (

      title %%a %%b

      set /a mult=%%a*%%b

      call :test !mult! %%a %%b

      set !mult!=%%a × %%b

    )

)

pause>nul



:test

    if defined %1 (

       echo !%1!=!mult!

       echo %2 × %3 =!mult!

       echo.)

Originally posted by youxi01 at 2006-11-24 22:58:
Appreciate the prime number search program of the moderator "Can't Help Loving You";

It seems that the moderator's solutions for 24, 25, 26 are in the form of solving equations哦

Wasn't solving chicken and rabbit problems in primary school done this way? Do we still need to solve equations?

There are quite a few numbers missing in the code on floor 88. For example:
2*27=54
3*18=54
6*9=54
1*54=54
But your code only outputs:
2*27=54
3*18=54