cd\
md a
cd a
for /l %%a in (1,1,100) do @md %%a
That's it
I tried it
md a
cd a
for /l %%a in (1,1,100) do @md %%a
That's it
I tried it
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Originally posted by haiou327 at 2007-5-12 06:31 PM:
What does /l mean here?